<span>Y = 2x + 4
16x + 4y = 40
substitute </span>Y = 2x + 4 into <span>16x + 4y = 40
</span><span>16x + 4y = 40
</span>16x + 4(2x + 4) = 40
16x + 8x + 16 = 40
24x = 40 - 16
24x = 24
x = 1
Y = 2x + 4
Y = 2(1) + 4
Y = 6
answer (1, 6)
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
Answer: jackson is 12
explanation:
let the age be represented by x
jackson is 2 times older than shelly so
2x is jackson’s age and x is shelly’s age
since the sum of their ages is 18 then:
2x + x = 18
solve:
3x = 18 ➔ divide by 3 on both sides
x = 6
so now we know shelly is 6
jackson is 2 times older than her so:
2(6) = 12
