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algol13
3 years ago
9

Based on its degree, what kind of polynomial is this h(x)= -6x^3+2x-5

Mathematics
1 answer:
Lelechka [254]3 years ago
7 0

Answer:

cubic polynomial

Step-by-step explanation:

Given polynomial is \[h(x)=-6x^{3}+2x-5\]

A polynomial of degree 1 is a linear polynomial.

A polynomial of degree 2 is a quadratic polynomial.

A polynomial of degree 3 is a cubic polynomial.

In this case the exponent with the maximum value in the polynomial is 3.

Hence the degree of the polynomial h(x) is 3.

Hence the given polynomial is a cubic polynomial.

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For 36 3 6 13. For 48 4 8 24. I think there are more but I can't think of them
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4 years ago
Harvard University accepts 6 students for every 100 applicants. How many students will be accepted in 850 applicants apply for a
LenKa [72]

Answer:

51 students.

Step-by-step explanation:

First you need to establish a rate 6/100+3/50

8*100=800   6*8=48

3/50

850-800=50   3/50

48+3=51



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3 years ago
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URGENT!! Really need help on this test
Katyanochek1 [597]

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G= L &M

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7 0
3 years ago
1. Triangle STU with vertices S(-4, 2) T(5, -1),
Alexus [3.1K]

Answer:

S’ (-5,-3)

T’ (4,-6)

U’ (-3,-7)

Step-by-step explanation:

Basically, we want to apply the given transformation rule of the axes to get the coordinates of the images

The rule is that we subtract 1 from the x-coordinates and also subtract 5 from the y-coordinates

Thus, we proceed as follows;

S’ = (-4-1, 2-5) = (-5,-3)

T’ = (5-1, -1-5) = (4,-6)

U’ = (-2-1,-2-5) = (-3,-7)

4 0
3 years ago
Hellllllllllllllllllllllllllp
murzikaleks [220]

Answer:

\begin{cases}y=-5x+1\\y=5x-4 \end{cases}

Step-by-step explanation:

Slope-intercept form of a <u>linear equation</u>:

\boxed{y=mx+b}

where:

  • m is the slope.
  • b is the y-intercept (where the line crosses the y-axis).

<u>Slope formula</u>

\boxed{\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}}

<u>Equation 1</u>

<u />

Define two points on the line:

  • \textsf{Let }(x_1,y_1)=(-1, 6)
  • \textsf{Let }(x_2,y_2)=(0, 1)

<u>Substitute</u> the defined points into the slope formula:

\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{1-6}{0-(-1)}=-5

From inspection of the graph, the line crosses the y-axis at y = 1 and so the y-intercept is 1.

Substitute the found slope and y-intercept into the slope-intercept formula to create an equation for the line:

y=-5x+1

<u>Equation 2</u>

<u />

Define two points on the line:

  • \textsf{Let }(x_1,y_1)=(1, 1)
  • \textsf{Let }(x_2,y_2)=(0, -4)

<u>Substitute</u> the defined points into the slope formula:

\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-4-1}{0-1}=5

From inspection of the graph, the line crosses the y-axis at y = -4 and so the y-intercept is -4.

Substitute the found slope and y-intercept into the slope-intercept formula to create an equation for the line:

y=5x-4

<u>Conclusion</u>

Therefore, the system of linear equations shown by the graph is:

\begin{cases}y=-5x+1\\y=5x-4 \end{cases}

Learn more about systems of linear equations here:

brainly.com/question/28164947

brainly.com/question/28093918

5 0
2 years ago
Read 2 more answers
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