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svet-max [94.6K]
3 years ago
11

5(4x-4)+2(13-5x)-3(3x+4)=-3 solve the equation. heLP

Mathematics
1 answer:
adell [148]3 years ago
6 0

The answer is x=3

Im sure of it.

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Four times the sum of three consecutive odd integers is seven hundred sixty-five less than three times the product of the larger
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Answer:

The consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

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Let the three consecutive odd integers be: x-2,x\ and \ x+2

The condition given is:

4[x-2+x+x+2]=3x(x+2)-765

Solve this for <em>x</em> as follows:

4[x-2+x+x+2]=3x(x+2)-765\\4\times 3x=3x^{2}+6x-765\\3x^{2}-6x-765=0\\x^{2}-2x-255=0\\x^{2}-17x+15x-255=0\\x(x-17)+15(x-17)=0\\(x-17)(x+15)=0

  • If (x-17)=0 then the value of <em>x</em> is 17.

       The odd numbers are:

          x-2=17-2=15\\x=17\\x+2=17+2=19

  • If (x+15)=0 then the value of <em>x</em> is -15.

       The odd numbers are:

         x-2=-15-2=-17\\x=-15\\x+2=-15+2=-13

Thus, the consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

7 0
3 years ago
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