3 years ago

HIGHER POINTS Solve for m<A

Mathematics

1 answer:

Musya8 [376]3 years ago

6 0

Answer:

The answer should be about 114.

Step-by-step explanation:

Of you look at the shape of the other angles. B and D seem to be about 90 and the shape of A is just a little bit bigger than ninety. I started by adding 78, 90, and 90 together which gave me 246. Then I subtracted 246 from 360 which gave me 114. I had estimated the answer to be around 110.

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The point (5, −2) is on the terminal ray of angle θ, which is in standard position. Without evaluating, explain how you would fi

Anni [7]

1. Check the picture attached.

let P, M, N be the points :P(5, -2), M(5, 0), N(0, -2)

ABP is the angle with measure ∅, where BA is the initial ray and BP the terminal ray.

2. m(PNM)=∅ as can be easily checked

In triangle PNM, NP=5, PM=2 and NM= $\sqrt{ 5^{2} + 2^{2} }= \sqrt{25+4}= \sqrt{29}$ units

3. let opp=opposite side, adj=adjecent side, hyp=hypothenuse

sin ∅ = opp/hyp= $\frac{2}{\sqrt{29}}$

cos ∅ = adj/hyp= $\frac{5}{\sqrt{29}}$

tan ∅ = opp/adj=2/5

cot ∅ = adj/opp=5/2

sec ∅ = hyp/adj= $\frac{\sqrt{29}}{5}$

csc ∅ = hyp/opp= $\frac{\sqrt{29}}{2}$