Solve the matrix equation for X.

Mathematics

2 answers:

Sedbober [7]3 years ago

8 0

See the attached picture:

Mama L [17]3 years ago

3 0

Answer:

$\large\boxed{\left[\begin{array}{ccc}-2&11\\-1&10\end{array}\right]}$

Step-by-step explanation:

$\left[\begin{array}{ccc}8&-7\\1&-5\end{array}\right] +X=\left[\begin{array}{ccc}6&4\\0&5\end{array}\right]\\\\\left[\begin{array}{ccc}8&-7\\1&-5\end{array}\right] -\left[\begin{array}{ccc}8&-7\\1&-5\end{array}\right]+X=\left[\begin{array}{ccc}6&4\\0&5\end{array}\right] -\left[\begin{array}{ccc}8&-7\\1&-5\end{array}\right]\\\\X=\left[\begin{array}{ccc}6-8&4-(-7)\\0-1&5-(-5)\end{array}\right]\\\\X=\left[\begin{array}{ccc}-2&11\\-1&10\end{array}\right]$

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Which is the graph of the cube root function f(x) = RootIndex 3 StartRoot x EndRoot?

lara [203]

Answer:

<h3>On a coordinate plane, a cube root function goes through (negative 8, negative 2), has an inflection point at (0, 0), and goes thorugh (8, 2).</h3>

Step-by-step explanation:

$f(x)=\sqrt[3]{x}\\\\f(-8)=\sqrt[3]{-8}=-2\to(-8,\ -2)\\\\f(0)=\sqrt[3]{0}=0\to(0,\ 0)\\\\f(8)=\sqrt[3]{8}=2\to(8,\ 2)\\\\\\\sqrt[3]{a}=b\iff b^3=a\\\\\text{Therefore:}\\\\\sqrt[3]{-8}=-2\ \text{because}\ (-2)^3=-8\\\sqrt[3]0=0\ \text{because}\ 0^3=0\\\sqrt[3]{8}=2\ \text{because}\ 2^3=8$