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Ainat [17]
3 years ago
6

Loretta and her family are going on vacation. Their destination is 610 miles from their home. Loretta is going to share some of

the driving with her dad. Her average speed while driving is 55 mph and her dad's average speed while driving is 65 mph. The plan is for Loretta to drive for this first 4 hours of the trip and her dad to drive for the remainder of the trip
Mathematics
1 answer:
alexandr402 [8]3 years ago
7 0
Loretta:
Average driving speed = 55 mph
Time = 4 hours
Distance traveled = 55*4 = 220 miles

Dad:
Average driving speed = 65 mph
Let x =  hours driven
Distance traveled = 65x miles

The length of the trip is 610 miles, therefore
65x + 220 = 610
65x = 390
x = 6  hours

Answer: Loretta's dad drove for 6 hours.
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Step-by-step explanation:

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3 years ago
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Secants L J and L M intersect and form an angle at point L. Solve for x.
german

Answer:

x = 14  

Step-by-step explanation:

Assume your diagram is like the one below.

The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."

For your diagram, that means

\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}

Check:

\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}

It checks.

6 0
3 years ago
in the unted states, the height of men are normally distributed with the mean 69 inches and standard deviation 2.8 inches. If 16
yaroslaw [1]

Answer:

Probability that their mean height is less than 68 inches is 0.0764.

Step-by-step explanation:

We are given that in the united states, the height of men are normally distributed with the mean 69 inches and standard deviation 2.8 inches.

Also, 16 men are randomly selected.

<em>Let </em>\bar X<em> = sample mean height</em>

The z-score probability distribution for sample mean is given by;

              Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean height = 69 inches

            \sigma = population standard deviation = 2.8 inches

            n = sample of men = 16

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the mean height of 16 randomly selected men is less than 68 inches is given by = P(\bar X < 68 inches)

 P(\bar X < 68 inches) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{68-69}{\frac{2.8}{\sqrt{16} } } ) = P(Z < -1.43) = 1 - P(Z \leq 1.43)

                                                           = 1 - 0.9236 = 0.0764

<em>Now, in the z table the P(Z  x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.43 in the z table which has an area of 0.92364.</em>

Therefore, probability that their mean height is less than 68 inches is 0.0764.

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3 years ago
Emma earned a grade of 95% on her multiple choice history final that had a total of
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Answer:

171

Step-by-step explanation:

180×95/100

180×95=17100

17100/100=171.

That is how I got my answer.

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s2008m [1.1K]
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