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2 years ago

Solve : 3[3[3]-2] square 2 -3[6-4] square 2 please help me

1 answer:

5 0

What are the brackets for? o and im srry for asking but could u mark this "answer" brainliest?? i just need one more to lvl up Im srry ik this isnt an answer but it would mean the world to me if u did
:D

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in a certain year the average e-mail user sent or received 148 e-mails each day. The number of e-mails received was 4 more than

Lorico [155]

Answer:

1136 received each day

Step-by-step explanation:

148(2)+4= 1136

8 0

2 years ago

If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .

The area (in square inches) of the circle that the hexagon did not cover would be:

$\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}$ .

3 0

2 years ago

I need help asap!! please!!

andre [41]

Wouldnt it be a dot on the line right in between 75 and 76 pointing towards the left? im not sure

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3 years ago

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Principal = $8100; rate = 17%; time = 7 years What is the amount of interest earned?

miskamm [114]

<span>it must be nnnnnnnnnnnnnnnnnnnnnnnnn
4.37%

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2 years ago

Mike's biweekly salary is $2345.00. How much does he make<br> each week?

Aloiza [94]

He makes 1,172.50. you find this by dividing 2345 by 2 (since that’s his BI weekly salary which means every 2 weeks he gets paid) when you divide by 2 you get 1,172.50

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2 years ago

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