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julsineya [31]
3 years ago
5

A ship traveled for a total of 72 miles over the course of 6 hours. Heading south, the ship traveled at an average speed of 13 m

iles per hour, and heading east, it traveled at an average speed of 10 miles per hour. For how many hours was the ahi heading east?
Mathematics
1 answer:
Alexxx [7]3 years ago
3 0
Recall your d = rt, distance = rate * time

the rate going south is 13, the rate going east is 10

it took a total amount of 6hours and 72miles for the whole travel

so.. if going say hmmm South, it covered a distance of "d", then going East it covered a distance of the slack from 72 and "d", it covered "72 - d" miles

so, if going South it took "t" hours, then going East it took the slack from 6 and "t", or "6 - t" hours

thus      \bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
South&d&13&t\\
East&72-d&10&6-t
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=13t\\
72-d=10(6-t)\\
----------\\
72-\boxed{13t}=10(6-t)
\end{cases}

solve for "t"

so, it travelled East for 6-t hours
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

Make a proportion

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Bart company charges a lower rate. It is lower by rate $ 0.5 per hour

<h3><u>Solution:</u></h3>

Given that Ace bike rentals rents bikes for $28 per day. Renters can keep the bike for 8 hours

Also given that Bart's bikes rents bikes for $30 per day. Renters can keep the bike for 10 hours

To find: company that charges lower rate

Let us find the hourly rate of Ace and Bart

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<em><u>Hourly rate of Ace company:</u></em>

Rental price = $28

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\text {hourly rate }=\frac{28}{8}=3.5

So the hourly rate of Ace company is $ 3.5 per hour

<em><u>Hourly rate of Bart company:</u></em>

Rental price = $ 30

total time in a day 10 hours

\text {hourly rate }=\frac{30}{10}=3

So the hourly rate of Bart company is $ 3 per hour

<em><u>Comparing hourly rate of both companies</u></em>

Ace company is $ 3.5 per hour

Bart company is $ 3 per hour

Bart company < Ace company

3 < 3.5

Thus bart company charges a lower rate

<h3><em><u>How much lower?</u></em></h3>

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Answer:

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Step-by-step explanation:

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