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julsineya [31]
3 years ago
5

A ship traveled for a total of 72 miles over the course of 6 hours. Heading south, the ship traveled at an average speed of 13 m

iles per hour, and heading east, it traveled at an average speed of 10 miles per hour. For how many hours was the ahi heading east?
Mathematics
1 answer:
Alexxx [7]3 years ago
3 0
Recall your d = rt, distance = rate * time

the rate going south is 13, the rate going east is 10

it took a total amount of 6hours and 72miles for the whole travel

so.. if going say hmmm South, it covered a distance of "d", then going East it covered a distance of the slack from 72 and "d", it covered "72 - d" miles

so, if going South it took "t" hours, then going East it took the slack from 6 and "t", or "6 - t" hours

thus      \bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
South&d&13&t\\
East&72-d&10&6-t
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=13t\\
72-d=10(6-t)\\
----------\\
72-\boxed{13t}=10(6-t)
\end{cases}

solve for "t"

so, it travelled East for 6-t hours
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8 0
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A) Find the value of N if, Kn has 105 edges.
blagie [28]

The number of edges can be calculated from the number of vertices.

  • <em>There are 14 vertices for 105 edges</em>
  • <em>There are 200 vertices for 19900 edges</em>

The variable N is used to always represent the number of vertices.

So, we represent the edges as:

E \to Edges

<u />

<u>(a) The value of N for 105 edges</u>

The relationship between N and E is:

E = \frac{N \times (N - 1)}{2}

Substitute 105 for E

105 = \frac{N \times (N - 1)}{2}

Multiply through by 2

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210 = N^2  - N

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N^2 - N - 210 = 0

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Factorize

N(N +14) - 15(N + 14) = 0

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<u>(b) The value of N for 19900 edges</u>

We have:

E = \frac{N \times (N - 1)}{2}

Substitute 19900 for E

19900 = \frac{N \times (N - 1)}{2}

Multiply through by 2

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39800= N^2  - N

Rewrite as:

N^2 - N - 39800= 0

Expand

N^2 +199N - 200N - 39800= 0

Factorize

N(N +199) - 200(N + 199) = 0

Factor out N + 199

(N + 199) (N - 200) = 0

Solve for N

N = 200 or N = -199

The number of vertices (N) cannot be negative. So:

N = 200

<em>Hence, there are 200 vertices for 19900 edges</em>

Read more about vertices and edges at:

brainly.com/question/22118318

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