Write a word problem that involves combining three equal groups

25h to the power of 10 +18

lesya692 [45]

Answer:

1.509909034 x10 ^36

Step-by-step explanation:

10 plus 18 is 28

Then you would multiply 28 by 25 numbers of itself.

6 0

3 years ago

PLEASE HELP ME!!! IM STRUGGLING

kakasveta [241]

A is 0.

B is 7.

C. is 3.

D is 0.

I dont know E.

F is 3.

G is 0.

8 0

3 years ago

A ticket printer made 450 tickets in 9 minutes. Another ticket printer made tickets for 5 minutes at twice the rate of the first

OlgaM077 [116]

Answer:

500

Step-by-step explanation:

Rate at which first ticket printer works is 450/9 = 50 tickets per minute

Speed of second ticket printer is twice than that of the first.

So, speed of second printer is 100 tickets per minute.

In 5 minutes,second printer made 500 tickets

8 0

3 years ago

A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in

erica [24]

Answer:

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$n=10$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =0.0217$ represent the sample variance

$\sigma^2_0 =0.12^2= 0.0144$ represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 0.0144$

Alternative hypothesis: $\sigma^2 \neq 0.0144$

The statistic can be calculated like this;

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

$\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54$

The degrees of freedom are:

$df=n-1=10-1=9$

Now we can calculate the p value using the alternative hypothesis:

$p_v =2*P(\chi^2 >13.54)=0.279$

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0

3 years ago

(07.01 LC)

Elanso [62]

Forth degree trinomial because we have a number that’s to the exponent of four and we have 3 terms.

6 0

3 years ago