Ask question

Ask question

All categories

2 years ago

9

Plz help quick. This question is on a quiz in Edg 2020 whoever answered first will get brainliest and I will be giving 50 points

to each person that answer.

2 answers:

Archy [21]2 years ago

7 0

Did you try A B and D

lys-0071 [83]2 years ago

4 0

Answer:

A B and D

Step-by-step explanation:

You might be interested in

Find , , and if and terminates in quadrant .

ioda

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

STEP - BY - STEP EXPLANATION

What to find?

• sin2x

,

• cos2x

,

• tan2x

Given:

tanx = 2/3 = opposite / adjacent

We need to first make a sketch of the given problem.

Let h be the hypotenuse.

We need to find sinx and cos x, but to find sinx and cosx, first determine the value of h.

Using the Pythagoras theorem;

hypotenuse² = opposite² + adjacent²

h² = 2² + 3²

h² = 4 + 9

h² =13

Take the square root of both-side of the equation.

h =√13

This implies that hypotenuse = √13

We can now proceed to find the values of ainx and cosx.

Using the trigonometric ratio;

$\sin x=\frac{opposite}{\text{hypotenuse}}=\frac{2}{\sqrt[]{13}}$ $\cos x=\frac{adjacent}{\text{hypotenuse}}=\frac{3}{\sqrt[]{13}}$

And we know that tanx =2/3

From the trigonometric identity;

sin 2x = 2sinxcosx

Substitute the value of sinx , cosx and then simplify.

$\sin 2x=2(\frac{2}{\sqrt[]{13}})(\frac{3}{\sqrt[]{13}})$ $=\frac{12}{13}$

Hence, sin2x = 12/13

cos2x = cos²x - sin²x

Substitute the value of cosx, sinx and simplify.

$\begin{gathered} \cos 2x=(\frac{3}{\sqrt[]{13}})^2-(\frac{2}{\sqrt[]{13}})^2 \\ \\ =\frac{9}{13}-\frac{4}{13} \\ =\frac{5}{13} \end{gathered}$

Hence, cos2x = 5/13

tan2x = 2tanx / 1- tan²x

$\tan 2x=\frac{2\tan x}{1-\tan ^2x}$ $=\frac{2(\frac{2}{3})}{1-(\frac{2}{3})^2}$ $=\frac{\frac{4}{3}}{1-\frac{4}{9}}$ $=\frac{\frac{4}{3}}{\frac{9-4}{9}}$ $=\frac{\frac{4}{3}}{\frac{5}{9}}$ $=\frac{4}{3}\times\frac{9}{5}=\frac{4}{1}\times\frac{3}{5}=\frac{12}{5}$

OR

$\tan 2x=\frac{\sin 2x}{\cos 2x}=\frac{\frac{12}{13}}{\frac{5}{13}}=\frac{12}{5}$

Hence, tan2x = 12/5

Therefore,

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

3 0

1 year ago

If the label of a can of yams were cut off and laid flat, which expression would give the area, A, of the label with the measure

Damm [24]

I think you are missing information to solve this problem. Should there me an image attached to this question.

Either way, to solve for the label, the label would most likely me a rectangle when laid flat.

It's dimensions would be length x height.

Where height is most likely "h"
and
length is most likely the circumference (2πr)

Thus the possible answers are either:

B or C

I can't answer it until I see an image when more detail.

Hope this helps!

7 0

3 years ago

G^4+ 5h<br> when g=2 & h=4

il63 [147K]

Answer: <em>36</em>

<em />

Step-by-step explanation:

<em>g^4+5h</em>

<em>2</em><em>^4+5(</em><em>4</em><em>)</em>

<em>16+20</em>

<em>36</em>

7 0

2 years ago

Will mark Brainliest

Ivahew [28]

Answer:

57.39

[tex]440 \: ( 1 + \frac{5t}{46 + \: {t}^{2} } ) \\ 440 \: ( \frac{6t}{46 {t}^{2} } ) \: ( \: multiply \: 440 \times 6t) \\ \frac{2640}{46} \\ = 57.39 or 57.30

8 0

2 years ago

Given the quadratic relation y = -x2 + 6x - 6, a) write the equation in vertex form b) graph the quadratic relation (using noteb

Mekhanik [1.2K]

<h3>Answer:</h3>

y = -(x -3)² +3 . . . . (agrees with your answer)
see the attachment for a graph

<h3>Step-by-step explanation:</h3>

Factoring the leading -1 from the first two terms, we have ...

... y = -(x² -6x) -6

Adding 9 inside parentheses to complete the square, then adding the opposite amount outside parentheses, we have ...

... y = -(x² -6x +9) -6 +9

... y = -(x -3)² +3

8 0

3 years ago