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attashe74 [19]
3 years ago
12

If the translation is (x+1, y-4) and the image is (1,7), what is the preimage

Mathematics
1 answer:
EleoNora [17]3 years ago
4 0

Answer:

The pre-image is the point (0,11)

Step-by-step explanation:

we know that

The rule of the translation is equal to

pre-mage------> image

(x,y) -----> (x+1,y-4)

so

we have that

(x+1,y-4)=(1,7)

so

x+1=1 -----> x=1-1=0

y-4=7 ----> y=7+4=11

therefore

The pre-image is the point (0,11)

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x^2 = 100/16

x^2 = 6.25

x = (+-) sqrt 6.25

x = (+-) 2.5

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(6^5/7^3)^2

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((6 (6^2)^2)/343)^2

6^2 = 36:
((6×36^2)/343)^2

 | | 3 | 6
× | | 3 | 6
 | 2 | 1 | 6
1 | 0 | 8 | 0
1 | 2 | 9 | 6:
((6×1296)/343)^2

6×1296 = 7776:
(7776/343)^2

(7776/343)^2 = 7776^2/343^2:
7776^2/343^2

 | | | | 7 | 7 | 7 | 6
× | | | | 7 | 7 | 7 | 6
 | | | 4 | 6 | 6 | 5 | 6
 | | 5 | 4 | 4 | 3 | 2 | 0
 | 5 | 4 | 4 | 3 | 2 | 0 | 0
5 | 4 | 4 | 3 | 2 | 0 | 0 | 0
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 | | | 3 | 4 | 3
× | | | 3 | 4 | 3
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1 | 0 | 2 | 9 | 0 | 0
1 | 1 | 7 | 6 | 4 | 9:

Answer: 60466176/117649
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