Question

There are 11 seats in a vehicle. How many ways can 11 people be seated if only 2 can drive

Answer 1

Answer:

They can be seater in 7,257,600 ways

Step-by-step explanation:

Arrangment formula:

Number of ways that n elements can be arranged, that is, distributed in n places is:

$A_{n} = n!$

In this question:

11 seats(driver and other 10).

Only 2 people can drive.

So

The driver can be 2 people.

The other 10 people are arranged in 10 positions.

$T = 2A_{10} = 2*10! = 7257600$

They can be seater in 7,257,600 ways