Answer:
Expected number of guests is 100.4.
Step-by-step explanation:
It is given that there are 161 guest if there is a heavy snow fall.
Also, the probability for a heavy snow fall is 0.40.
Therefore, P(X = 161) =0.4.
It is also given that there are 60 guests if there is a light snow fall.
The probability for a light snow fall is 1 - 0.4 = 0.6.
Therefore, P(X = 60) = 0.6.
Expected number of guests = (161)P(X = 161) + (60)P(X = 60)
= 161(0.4) + 60(0.6)
= 64.4 + 36
= 100.4
I believe it’s C, 21 divided by 7. This one doesn’t leave any extra mugs out cause 21 divided by 7 is 3, leaving 7 mugs per 3 shelves and having none left.
Answer:
If Cora runs 1/2 mile per week and x is the number of weeks, then she will run 5+1/2x. Then determine how many weeks are in two and a half months (depends on which month it is as there are less weeks in February than in January!) but we could estimate 6.
For Hana, you will have 3+ 3/4 x
Step-by-step explanation:
First equation is y=5+1/2 x and then plug 6 in for x to solve for y. the second equation is y=3+3/4x and plug in 6.
Answer:
3200 people
Step-by-step explanation:
p = The frequency of the dominant gene
q = The frequency of the recessive gene
p+q = 1
⇒p = 1-q
⇒p = 1-0.2
⇒p = 0.8
Hardy-Weinberg formula
p² + 2pq + q² = 1
Now for heterozygous trait
2pq = 2×0.8×0.2 = 0.32
Multiplying with the population
0.32×10000 = 3200
∴ 3200 people would be expected to be heterozygous for this trait.
