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sweet-ann [11.9K]
4 years ago
10

If p=-2 and q=-5, is the value of p/q equivalent to 2/5

Mathematics
1 answer:
Serhud [2]4 years ago
7 0
Yes as the even times the occurrence of negative signs makes the answer positive.
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URGENT HELP THIS IS FOR DWREAD ONLY
QveST [7]

Answer:

(-1,0) and (3,0)

Step-by-step explanation:

The x-intercepts are the points where the graph crosses the x-axis. (-1,0) and (3,0)

6 0
3 years ago
Hacksaw’s Boats of St. Lucia takes tourists on a daily whale/dolphinwatch cruise. Their brochure claims an 80% chance of siting
Fittoniya [83]

Answer:

The probability you see a dolphin or a whale on both days is 0.64

Step-by-step explanation:

Consider the provided information.

It is given that the brochure claims an 80% chance of siting a dolphin or a whale.

The provided claims can be written as: 80% or 0.80

Let say first day you see a dolphin or a whale and same happen on the next day.

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0.80 × 0.80 = 0.64

Probability of see them on both days is 0.64

Hence, the probability you see a dolphin or a whale on both days is 0.64

5 0
3 years ago
Plz help me i did it but messed up some ware plz help . 5x5=4x5+9=
Lyrx [107]

Answer: 25=29

Step-by-step explanation:5x5=25

4x5+9=29

5 0
3 years ago
Read 2 more answers
What number has exactly 6 factors
RoseWind [281]
The factors of  12  are  1,  2,  3,  4,  6, and  12 .

The factors of  32  are  1,  2,  4,  8,  16, and  32 .
4 0
3 years ago
Read 2 more answers
The atmospheric pressure P on a balloon or in aircraft decreases with increasing height . This pressure measured in Millimeters
Vesnalui [34]

Answer:

(A)   5.47 km

(B)   1.38 km

Step-by-step explanation:

The relationship between Pressure (mmHg) and Height (km) is given by the equation below:

p =760 e⁻ 0.145h----------------------------------------------------- (1)

(a) The height of the aircraft can be calculated by making 'h' the subject of equation (1)

In (p/760) = -0.145 h

h = -In (p/760) /0.145

h= In (760/p)/ 0.145------------------------------------------------- (2)

For the aircraft, p =344 mmHg; substituting into (2)

h = In (760/344)/0.145

   = 0.7926/0.145

   = 5.4662 km

   ≈ 5.47 km

(b) p= 622 mmHg at the mountain top. Substituting into equation  (2) we have:

h = In (760/622)/0.145

  = 0.2003 / 0.145

  =  1.3813 km

  ≈  1.38 km

4 0
3 years ago
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