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3 years ago

Help please! I don’t know how to do this.

Mathematics

1 answer:

Akimi4 [234]3 years ago

5 0

... I don’t either... hold on lemme try I will be back soon I’m doing the problem

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2 R congruence theorem

Gnoma [55]

Answer:

ghj

Step-by-step explanation:

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4 years ago

Read 2 more answers

Order the values from least to greatest. -3, |-8|, 0, |4|, -1, 2

weqwewe [10]

Answer: -3, -1, 0, 2, |4|, |-8|

The absolute values would be positive, which would lead to them being after the 0.

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3 years ago

The rate (gallons per day) at which a pond loses water due to evaporation from one day after observation has started is give by

Andreyy89

Answer: see table below

Step-by-step explanation:

$\left\begin{array}{c|l}T&\qquad w(t)\\1&\dfrac{1}{1^2}=1\implies 1.00\\\\2&\dfrac{1}{2^2}=\dfrac{1}{4}\implies 0.25\\\\10&\dfrac{1}{10^2}=\dfrac{1}{100}\implies 0.01\\\\50&\dfrac{1}{50^2}=\dfrac{1}{2500}\implies 0.0004\\\\100&\dfrac{1}{100^2}=\dfrac{1}{10000}\implies 0.0001\\\\200&\dfrac{1}{200^2}=\dfrac{1}{40000}\implies 0.000025\\\\500&\dfrac{1}{500^2}=\dfrac{1}{250000}\implies 0.000004\\\\1000&\dfrac{1}{1000^2}=\dfrac{1}{100000}\implies 0.000001\\\end{array}\right$

4 0

3 years ago

One car travel 56 miles per hour and another travels 31 miles per hour. If they start from the same place at the same time and t

Vitek1552 [10]

After 3 hours, the faster car will be 75 miles ahead of the slower car.

Step-by-step explanation:

Given,

Speed of first car = 56 miles per hour

Speed of second car = 31 miles per hour

Let,

x be the number of hours.

Distance covered by first car = Speed * time = 56x

Distance covered by second car = 31x

According to given statement;

Difference between distance covered by both cars = 75 miles

Distance of faster car - Distance of slower car = 75 miles

$56x-31x=75\\25x=75$

Dividing both sides by 25

$\frac{25x}{25}=\frac{75}{25}\\x=3$

After 3 hours, the faster car will be 75 miles ahead of the slower car.

Keywords: subtraction, division

Learn more about subtraction at:

#LearnwithBrainly

4 0

4 years ago

Rad 18x^5y + Rad 32xy^3 - Rad 128xy

True [87]

Sqrt(18x^5y) + sqrt(32xy^3) - sqrt(128xy)
You may separate the roots to produce solvable square roots!

sqrt(9x^4)*sqrt(2xy) + sqrt(16y^2)*sqrt(2xy) - sqrt(64)*sqrt(2xy)

Simplifying makes it ...
(3x^2 + 4y - 8)*sqrt(2xy)
This should be the closest you can get to a simplified equation.

5 0

3 years ago