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3 years ago

Is the relationship in the table linear,exponential,or neither? Explain how you know.

Mathematics

1 answer:

RoseWind [281]3 years ago

7 0

Exponential Relationship because the x-values are increasing [by 1] and the y-values are being multiplied [by 2].

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Standard printer paper has a thickness of 0.1mm. write an equation for a function that should approximately the thickness of a s

ladessa [460]

Folding a paper will make it thickness become double from it before.
Unfolded paper has 1 thickness
1 times folded paper has 2 thickness
2 times folded paper has 4 thickness
3 times folded paper has 8 thickness

From here it is clear that the pattern is $2^{n}$ . SInce the paper is 0.1mm, then the function would be:
f(n)= $2^{n}$ x 0.1mm

4 0

2 years ago

Find the distance between the points of intersection of the graphs of the functions.

Viefleur [7K]

Answer:

Find the value of x and y in coordinate form, that'll be the point of intersection.

Question 1

${ \rm{y = {x}^{2} - 3x + 4 }} \\ { \boxed{ \tt{but \: y = x + 1 \: }}} \\ \\ { \rm{(x + 1) = {x}^{2} - 3x + 4 }} \\ \\ { \rm{ {x}^{2} - 4x + 3 = 0 }} \\ \\ { \rm{(x - 3)(x - 1) = 0}} \\ \\ { \boxed{ \rm{x_{1} = 3 \: \: and \: \: x _{2} = 1}}} \\ \\ { \boxed{ \tt{remember \: y = x + 1}}} \\ \\ { \rm{y _{1} = 4 \: \: and \: \: y _{2} = 2 }}$

Therefore, points of intersection are two

Answer:  (3, 4) and (1, 2)

Question 2:

Following the steps as in question 1

${ \rm{y = {x}^{2} - 4}} \\ \\{ \rm{2x - 4 = {x}^{2} - 4}} \\ \\ { \rm{ {x}^{2} = 2x }} \\ \\ { \boxed{ \rm{x = 2}}} \\ { \tt{remember : \: y = 2x - 4 }} \\ { \boxed{ \rm{y = 0}}}$

Answer: (2, 0)

7 0

2 years ago

Read 2 more answers

Jane travels7 mph less than2 times as fast as Mike. Starting at the same point and traveling in the same direction, they are198

Sphinxa [80]

Let:

Vj = Speed of jane

Vm = Speed of mike

d = distance

t = time

Jane travels 7 mph less than 2 times as fast as Mike, therefore:

Vj = 2Vm - 7

Remeber:

distance = speed*time

Distance traveled by mike:

d=Vm*t = Vm*6

Distance traveled by jane:

d + 198 = Vj*6

where:

Vj = 2Vm - 7

d + 198 = (2Vm-7)*6

Now, let:

d=Vm*6 (1)

d + 198 = (2Vm-7)*6 (2)

Replace (1) into (2)

6Vm + 198 = 12Vm - 42

Subtract 6Vm from both sides:

6Vm + 198 - 6Vm = 12Vm - 42 - 6Vm

198 = 6Vm - 42

Add 42 to both sides:

198 + 42 = 6Vm - 42 + 42

240 = 6Vm

Divide both sides by 6:

240/6 = 6Vm/6

40 = Vm

Vm = 40mph

Replace Vm into this equation Vj = 2Vm - 7 :

Vj = 2(40) - 7 = 80 - 7 = 73mph

4 0

1 year ago

24 girls are trying out for 12 spots on the cheerleading team. If you want to determine how many different groups of 12 girls ca

g100num [7]

I think permutation is the answer

5 0

3 years ago

Given y2 + 5y - 6 = (y + p)(y +q) find the values of p and q.

finlep [7]

Answer:

p = 6, q = - 1

Step-by-step explanation:

Factor the left side and compare to right side

y² + 5y - 6

Consider the factors of the constant term (- 6) which sum to give the coefficient of the y- term (+ 5)

The factors are + 6 and - 1, since

6 × - 1 = - 6 and 6 - 1 = + 5, thus

y² + 5y - 6 = (y + 6)(y - 1)

Compare with (y + p)(y + q) , then

p = 6 and q = - 1

5 0

3 years ago