Let
x--------> the time in minutes
y-------> an altitude in feet
we know that
For x=0 min y=0 ft
For x=50 min y=52,000 ft
so
the rate of change is equal to calculate the slope of the linear equation

Round to the nearest hundred-------->
therefore
<u>the answer is</u>

PS = PR + RS = 4x - 2 + 3x - 5 = 7x - 7.
Answer:
∠EFG = 48°
Step-by-step explanation:
As FH bisects ∠EFG , ∠EFH = ∠HFG .
We know that ∠EFH = (-5x + 89)° . So ∠HFG = ∠EFH = (-5x + 89)°
Also, ∠HFG + ∠EFH = ∠EFG
=> 2(-5x + 89)° = (61 - x)°
=> -10x + 178 = 61 - x
=> 10x - x = 178 - 61
=> 9x = 117
=> x = 117 / 9 = 13
Putting the value of 'x' in ∠EFG gives :-
(61 - x)° = (61 - 13)° = 48°