Given:
In the circle,
and
.
To find:
The following measures:
(a) 
(b) 
Solution:
According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.




In a cyclic quadrilateral, the opposite angles are supplementary angles.
UVWX is a cyclic quadrilateral. So,
[Opposite angles of a cyclic quadrilateral]
Now,
[Opposite angles of a cyclic quadrilateral]
Therefore,
and
.
So we have lengths a and b and are given:
2a+2b = 66 => a+b = 33 => a= 33-b
a*b = 272
plug in one into the other:
(33-b)b = 272 => -b^2 +33b - 272 = 0
Can be factored as (b-16)(b-17) = 0, if you don't "see" this immediately, use the well known abc formula to find b.
So a=16 and b=17 or vice versa.
The longest side
Think about it. The widest angle would leave a resulting long side to reach the ends of the angle
If you look at the picture, the side across from the widest angle has the longest length
Answer:
First point goes on -2
Step-by-step explanation:
Answer:
80
Step-by-step explanation:
Angle VSU = 100. Angles TSU is a linear pair with angle VSU so adding them together equals 180. 180-100=80.