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3 years ago

Why in division there is sometimes remaindres?

2 answers:

7 0

In division problems, if the division results in a decimal or fraction, (not a whole number), than it has a remainder. If the division results in a whole number, then there is no remainder, or a remainder of zero.

Examples:

6/3=2

6/4=1.5

MAXImum [283]3 years ago

3 0

The reason is because the number you are trying to divide into parts is not a factor of the number you are trying to divide into parts. so there fore there are left overs. Example: 28/3 ( 28 divided by 3). 3 only goes into 28 9 time (because 9*3 is 27) and then your answer would be 9 REMAINDER of 1 because the 3 cannot equally divide into 28. Hope this helps!

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Todo numero es divisible por 3, si al sumar el total de sus digitos, se obtiene un numero mutiplo del tres (se puede expresar co

Free_Kalibri [48]

Answer:

si, eso es correcto

Step-by-step explanation:

Espero que esto ayude a marcar el MÁS CEREBRAL !!!

7 0

3 years ago

Building a is 271 meters taller than building

kvv77 [185]

Let a and b represent the heights of the corresponding buildings (in meters).

... a = b +271 . . . . . . . a is 271 meters taller than b

... 2b -a = 211 . . . . . . if a is subtracted from twice b, the result is 211

Use the expression for a in the first equation to substitute for a in the second.

... 2b - (b+271) = 211

... b = 482 . . . . . . . . . . . simplify and add 271

... a = b +271 = 753

Building a is 753 meters tall; building b is 482 meters tall.

4 0

3 years ago

A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet

Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

$L_{1} = 2W_{1}$

Also, the area of the walkway of 2 feet wide is 448:

$W_{2} = 2 ft$

$A_{T} = W_{2}*L_{2} = 448 ft^{2}$

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

$A_{T} = A_{1} + A_{w}$ (1)

The area of the pool is given by:

$A_{1} = L_{1}*W_{1}$

$A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}$ (2)

And the area of the walkway is:

$A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}$ (3)

Where the length of the bigger rectangle is related to the lower rectangle as follows:

$L_{2} = 4 + L_{1} = 4 + 2W_{1}$ (4)

By entering equations (4), (3), and (2) into equation (1) we have:

$A_{T} = A_{1} + A_{w}$

$A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}$

$448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}$

$224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}$

$224 = W_{1}^{2} + 8 + 6W_{1}$

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

$L_{1} = 2W_{1} = 2*12 ft = 24 ft$

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!

8 0

3 years ago

Easy, need help, thanks.

TEA [102]

Answer:

A. 35 deg

Step-by-step explanation:

The triangles are congruent bu HL.

m<RCD = m<PCD = 35 deg

5 0

3 years ago

Read 2 more answers

Match each scenario involving projectile motion with the equation that describes the height of the object at time t. Tiles h = -

olga55 [171]

Answer:

h = -16t^2 + 73t + 5
h = -16t^2 + 5
h = -4.9t^2 + 73t + 1.5
h = -4.9t^2 + 1.5

Step-by-step explanation:

The general equation we use for ballistic motion is ...

$h(t)=\frac{1}{2}gt^2+v_0t+h_0$

where g is the acceleration due to gravity, v₀ is the initial upward velocity, and h₀ is the initial height.

The values of g commonly used are -32 ft/s², or -4.9 m/s². Units are consistent when the former is used with velocity in ft/s and height in feet. The latter is used when velocity is in m/s, and height is in meters.

_____

Dwayne throws a ball with an initial velocity of 73 feet/second. Dwayne holds the ball 5 feet off the ground before throwing it. (h = -16t^2 + 73t + 5)

A watermelon falls from a height of 5 feet to splatter on the ground below. (h = -16t^2 + 5)

Marcella shoots a foam dart at a target. She holds the dart gun 1.5 meters off the ground before firing. The dart leaves the gun traveling 73 meters/second. (h = -4.9t^2 + 73t + 1.5)

Greg drops a life raft off the side of a boat 1.5 meters above the water. (h = -4.9t^2 + 1.5)

_____

Additional comment on these scenarios

The dart and ball are described as being launched at 73 units per second. Generally, we expect launches of these kinds of objects to have a significant horizontal component. However, these equations are only for vertical motion, so we must assume the launches are straight up (or that the up-directed component of motion is 73 units/second).

4 0

3 years ago