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3 years ago

What’s the value of x in both a & b?

Mathematics

1 answer:

Paladinen [302]3 years ago

4 0

Answer:

a) 7

b) 2 2/7

Step-by-step explanation:

A) 2/7=2/x

x=7

B) 2/7=x/8

cross multiply

16=7x

x=16/7, or 2 2/7, or 2.2857

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Ksenya-84 [330]

Answer: use google

Step-by-step explanation:

Because y e s and because your wasting peoples time

3 0

3 years ago

The formula for depreciation is V=P(1-r)t where P is the beginning price of the asset, r is the annual rate of depreciation writ

Bad White [126]

Answer:

The value of the car after 5 years is $ 13,035 to the nearest dollar.

Step-by-step explanation:

The formula for depreciation is

$V=P(1-r)^t$

where $P=24,700\:dollars$ is the beginning price of the asset,

$r=12\%$ is the annual rate of depreciation written as a decimal,

$r=0.12$

$t=5$ is the number of years, and V is the value after t years.

Now substitute all these values into the formula to get,

$V=24,700(1-0.12)^5$

This simplifies to,

$V=24,700(0.88)^5$

$\Rightarrow V=24,700(0.5277319168)$

$\Rightarrow V=13,034.97834$

The value of the car after 5 years is $ 13,035 to the nearest dollar.

8 0

3 years ago

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ss7ja [257]

Answer:

the 4th one

Step-by-step explanation:

3 0

3 years ago

Solve the following using Substitution method 2x – 5y = -13 3x + 4y = 15

Digiron [165]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\left. \begin{array} { l } { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.$

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$2x-5y=-13, \: 3x+4y=15$

Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

$2x-5y=-13$

Add 5y to both sides of the equation.

$2x=5y-13$

Divide both sides by 2.

$x=\frac{1}{2}\left(5y-13\right) \\$

Multiply $\frac{1}{2}\\$ times 5y - 13.

$x=\frac{5}{2}y-\frac{13}{2} \\$

Substitute $\frac{5y-13}{2}\\$ for x in the other equation, 3x + 4y = 15.

$3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15 \\$

Multiply 3 times $\frac{5y-13}{2}\\$ .

$\frac{15}{2}y-\frac{39}{2}+4y=15 \\$

Add $\frac{15y}{2} \\$ to 4y.

$\frac{23}{2}y-\frac{39}{2}=15 \\$

Add $\frac{39}{2}\\$ to both sides of the equation.

$\frac{23}{2}y=\frac{69}{2} \\$

Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

$\large \underline{ \underline{ \sf \: y=3 }}$

Substitute 3 for y in $x=\frac{5}{2}y-\frac{13}{2}\\$ . Because the resulting equation contains only one variable, you can solve for x directly.

$x=\frac{5}{2}\times 3-\frac{13}{2} \\$

Multiply 5/2 times 3.

$x=\frac{15-13}{2} \\$

Add $-\frac{13}{2}\\$ to $\frac{15}{2}\\$ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

$\large\underline{ \underline{ \sf \: x=1 }}$

The system is now solved. The value of x & y will be 1 & 3 respectively.

$\huge\boxed{ \boxed{\bf \: x=1, \: y=3 }}$

8 0

3 years ago

Find the GCF 0f 12 and 18

melisa1 [442]

Answer:

Step-by-step explanation:

Using Euclid's algorithm, we divide the larger by the smaller. If the remainder is zero, the divisor is the GCF. Otherwise, we replace the larger with the remainder and repeat.

18 ÷ 12 = 1 r 6

12 ÷ 6 = 2 r 0 . . . . the GCF is 6

You can also factor the numbers and see what the common factors are.

18 = 2·3·3

12 = 2·2·3

The common factors are 2·3 = 6.

In the factorizations, we see 2 to powers of 1 and 2, and we see 3 to powers of 1 and 2. The GCF is the product of the common factors to their lowest powers: (2^1)(3^1) = (2)(3) = 6

8 0

2 years ago