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2 years ago

A triangle has a perimeter of 77 inches. What are the side lengths of a, b, and c?

Mathematics

1 answer:

Yuki888 [10]2 years ago

6 0

Answer:

I believe this is pathgorean theorem, which I did at the beginning of alegbra last year. It is basically finding the missing side of a triangle. (Trust me some of the easiest stuff you do all year) Below are my notes from last year. I hope it helps! Good Luck!!!

Step-by-step explanation:

Given two sides

If you know two other sides of the right triangle, it's the easiest option; all you need to do is apply the Pythagorean theorem:

a² + b² = c²

if leg a is the missing side, then transform the equation to the form when a is on one side, and take a square root:

a = √(c² - b²)

if leg b is unknown, then

b = √(c² - a²)

for hypotenuse c missing, the formula is

c = √(a² + b²)

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3 years ago

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In the equation 6x - 2 = -4x + 2, Spencer claims that the

Alinara [238K]

Answer:

Spencer is correct

Step-by-step explanation:

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2 years ago

Angel has an action figure collection of 300 action figures. He keeps 267 of the action figures on his wall. What percentage of

Veseljchak [2.6K]

Answer:

89% of Angel's action figure collection keeps on his wall.

Step-by-step explanation:

<u>Percentages</u>

To calculate the X% of a quantity Y, we must multiply both numbers and divide by 100:

X% of Y = X * Y / 100

For example, 15% of 780 = 15 * 780 / 100 = 117

If we want to know what percentage is m with respect to n, we proceed as follows:

percentage = m / n * 100%

Anges has a 300 action figures collection, 267 of which are kept on his wall. Here m=267, n=300, thus:

percentage = 267 / 300 * 100% = 89%

89% of Angel's action figure collection keeps on his wall.

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3 years ago

Plz..... Solve this questions for me...

faust18 [17]

$6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================$

$7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================$

$8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10$

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2 years ago

A boat starts from a port and moves 12 miles north and then moves 5 miles east. what is the present distance of the boat from th

disa [49]

If you sketch the path of the boat, you will form a right triangle towards the port. The distance from the port to the present position is the hypotenuse since it is opposite from the right angle formed by the 12 miles north and 5 miles east movement. Since it is a right triangle, use the Pythagorean Theorem to solve the hypotenuse.

Solution:

h² = o² + a²
h² = 12² + 5²
h² = 144 + 25
h² = 169
√h² = √169
h= 13

The present distance of the boat from the port is 13 miles.

7 0

2 years ago