Answer:
a. answer to a can be found in the attached file
b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=
0.24+0.06+0.05 = 0.35
c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?
Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07
Step-by-step explanation:
"A seed randomly blows around a complex habitat. It may land on any of three different soil types: a high-quality soil that gives a 0.8 chance of seed survival, a medium-quality soil that gives a 0.3 chance of survival, and a low-quality soil that gives only a 0.1 chance of survival. These three soil types (high, medium, and low) are present in the habitat in proportions of 30:20:50, respectively. The probability that a seed lands on a particular soil type is proportional to the frequency of that type in the habitat. a. Draw a probability tree to determine the probabilities of survival under all possible circumstances. b. What is the probability of survival of the seed, assuming that it lands"c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?
a. Find the probability tree as attached below
b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=
0.24+0.06+0.05 = 0.35
c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?
Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07
(12 x 16) = 192 + 8 = 200
Therefore the answer is 200 which when divided by 12 gives a quotient of 16 and a remainder of 8.
Answer:
See below
Step-by-step explanation:
a = 15 sqrt 2 sin 45
= 15 sqrt 2 * sqrt( 2 ) /2 = 15 * 2 /2 = 15
sin 60 = a/c
sqrt(3)/2 = 15/c
c = 15 / ( sqrt(3)/2) = 30 / sqrt 3 = 30 sqrt 3 /3 = 10 sqrt 3
Answer:
4 inches.
Step-by-step explanation:
24 32
---- = -----
3 x
Cross multiply.
24x = (32)(3) = 96.
96 / 24 = 4.
Hope this helped and good luck! (:
