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3 years ago

16 larger than the product of a and b. Change the statement into algebraic expression

Mathematics

1 answer:

avanturin [10]3 years ago

7 0

16>ab that is the answer to your question or you could put it as 16>a•b

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Connor is asked to find the probability of rolling a prime number on a die. He states that this is a simple event. True or false

Dafna1 [17]

The correct answer is true

5 0

2 years ago

Which of the following represent the same ratio?

eduard

Answer:2/3 and 2:3
Explanation

5 0

2 years ago

Can someone help me with this and have it step by step please

Sladkaya [172]

Answer:

should also be 40

Step-by-step explanation:

the measure of angle 1 is equivelent to angle two, since they both lie ont he same line.

8 0

3 years ago

Tamira invests $5,000 in an account that pays 4% annual interest. How much will there be in the account after 3 years if the int

Talja [164]

Answer:

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

Step-by-step explanation:

Tamira invests $5,000 in an account

Rate of interest = 4%

Time = 3 years

Case 1:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 1

Formula : $A=P(1+r)^t$

$A=5000(1+0.04)^3$

A=5624.32

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

Case 2:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 2

Formula : $A=P(1+\frac{r}{n})^{nt}$

$A=5000(1+\frac{0.04}{2})^{2 \times 3}$

A=5630.812

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

Case 3:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : $A=P(1+\frac{r}{n})^{nt}$

$A=5000(1+\frac{0.04}{4})^{4 \times 3}$

A=5634.125

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

Case 4:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : $A=P(1+\frac{r}{n})^{nt}$

$A=5000(1+\frac{0.04}{12})^{12 \times 3}$

A=5636.359

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

8 0

3 years ago

If 2^x=1/32, find the value of x

Dovator [93]

Answer:

In this equation x is equal to -5.

Step-by-step explanation:

In order to find this, we first have to note for the base (2) to be larger than the answer (1/32), the exponent would have to be negative. We also can note that 2^5 is equal to 32, which allows us to know that the negated version would give us 1/32.

2^-5 = 1/32

3 0

3 years ago