Which set of population data is the least dispersed from its mean? 2, 3, 2, 9 4, 0, 4, 0 6, 2, 2, 2 9, 3, 5, 3.
exis [7]
The set of data 6, 2, 2, 2 will have the least dispersion from its mean.
<h3 /><h3>What will be the mean?</h3>
From four sets of data, we take the mean of 6,2,2,2

So the mean will be

So the mean of the data (6,2,2,2) is 3 which has the least dispersion from its every data as compared to the other data
Thus the set of data 6, 2, 2, 2 will have the least dispersion from their mean.
<h3 />
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Answer:
4x +y = 3
Step-by-step explanation:
Perpendicular lines have slopes that are the negative reciprocals of one another. When the equation of the line is written in standard form like this, the equation of the perpendicular line can be written by swapping the x- and y-coefficients and negating one of them. Doing this much would give you ...
4x +y = (constant)
Note that we have chosen to make the equation read 4x+y, not -4x-y. The reason is that "standard form" requires the leading coefficient to be positive.
Now, you just need to make sure the constant is appropriate for the point you want the line to go through. So, it needs to be ...
4(2) +(-5) = constant = 3
The line of interest has equation ...
4x + y = 3
Answer:
She is incorrect
Step-by-step explanation:
Pythagorean theorem:
16^2+8^2
256+64=320
320 is 17.89
8^2+8^2
64+64=128
√128 is 11.31
Ada is incorrect. The length of diagonal SQ is bigger than the length of diagonal OM. But it is not two times bigger.
Answer:
AA Similarity Postulate
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent
step 1
Verify the proportion of the corresponding sides

substitute

----> is true
Corresponding sides are proportional
Triangle PQR is similar to Triangle PST
That means
Corresponding angles must be congruent
side QR is parallel side ST
and
----> by corresponding angles
--> by corresponding angles
so
PQR is similar to PST by AA Similarity Postulate
This problem can be solved from first principles, case by case. However, it can be solved systematically using the hypergeometric distribution, based on the characteristics of the problem:
- known number of defective and non-defective items.
- no replacement
- known number of items selected.
Let
a=number of defective items selected
A=total number of defective items
b=number of non-defective items selected
B=total number of non-defective items
Then
P(a,b)=C(A,a)C(B,b)/C(A+B,a+b)
where
C(n,r)=combination of r items selected from n,
A+B=total number of items
a+b=number of items selected
Given:
A=2
B=3
a+b=3
PMF:
P(0,3)=C(2,0)C(3,3)/C(5,3)=1*1/10=1/10
P(1,2)=C(2,1)C(3,2)/C(5,3)=2*3/10=6/10
P(2,0)=C(2,2)C(3,1)/C(5,3)=1*3/10=3/10
Check: (1+6+3)/10=1 ok
note: there are only two defectives, so the possible values of x are {0,1,2}
Therefore the
PMF:
{(0, 0.1),(1, 0.6),(2, 0.3)}