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Daniel [21]
3 years ago
12

In an insect colony there are 270 insects after 9 days. If there were initially 80 insects how long will it take the population

to grow to 800 insects?
Mathematics
1 answer:
Semenov [28]3 years ago
7 0

Answer:

The time it will take the population to grow to 800 insects is 17 days.

Step-by-step explanation:

The growth function of the insects is exponential.

The exponential growth function is:

y=a(1+r)^{t}

Here,

<em>y</em> = final value

<em>a</em> = initial value

<em>r</em> = growth rate

<em>t</em> = time taken

It is provided that there were 270 insects after 9 days and initially there were 80 insects.

Compute the value of <em>r</em> as follows:

y=a(1+r)^{t}\\\\270=80(1+r)^{9}\\\\3.375=(1+r)^{9}\\\\\ln(3.375)=9\cdot \ln(1+r)\\\\0.135155=\ln(1+r)\\\\1+r=1.14471\\\\r=0.145

Now, compute the time it will take the population to grow to 800 insects as follows:

800=80(1+0.145)^{t}\\\\10=(1.145)^{t}\\\\\ln(10)=t\cdot \ln(1.145)\\\\t=17.00522\\\\t\approx 17

Thus, the time it will take the population to grow to 800 insects is 17 days.

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The first three terms of a Fibonacci sequence are n 3n 4n find the sixth term I FB the sequence
Amiraneli [1.4K]

Answer:

<h2>18n</h2>

Step-by-step explanation:

In the Fibonacci sequence In mathematics, the Fibonacci numbers, commonly denoted Fn, form a sequence, called the Fibonacci sequence, such that each number is the sum of the two preceding ones, starting from 0 and 1.

Given data

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F6= F4+F5\\   F6= 7n+11n= 18n

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