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2 years ago

15

The table shows the total number of trees cut down by a logging company over a two-week period. What was the average rate of cha

nge between Day 9 and Day 14?

1 answer:

irina [24]2 years ago

7 0

Average rate of change = slope so lets get our y's and x's and plug them into y2-y1 / x2-x1. (14-9)/(308-195) and that equals 5/113

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What is the radius of a circle with an area of 50.24 square inches?

Vladimir [108]

Answer:

<h3>Area of a circle= πr²</h3><h2>50.24 = 3.14 *r²</h2><h2>r²= 50.24/3.14</h2><h2>r² =16</h2><h2>r= √16</h2><h2>r = 4</h2>

7 0

2 years ago

A 20% apple juice drink is mixed with a 100% apple juice drink. The function f(x)=(2)(1.0)+x(0.2)2+x models the concentration of

luda_lava [24]

Answer:

17.5

Step-by-step explanation:

Given that:

20% apple juice drink is mixed with a 100% apple juice drink.

$f(x)=\dfrac{(2)(0.1)+x(0.2)}{2+x}$

represents the concentration of apple juice in the drink when $x$ gallons of 20% drink are added to 2 gallons of pure juice.

Also, given that 6 gallons of 20% drink are added to the 2 gallons of pure juice.

To find:

The concentration of apple juice in the drink = ?

Solution:

Given the function:

$f(x)=\dfrac{(2)(0.1)+x(0.2)}{2+x}$

and

$x=6\ gallons$

$f(x)=\dfrac{(2)(0.1)+6(0.2)}{2+6}\\\Rightarrow f(x)=\dfrac{0.2+1.2}{8}\\\Rightarrow f(x)=\dfrac{1.4}{8}\\\Rightarrow f(x)=\bold{0.175}$

In percentage, the concentration 17.5.

7 0

2 years ago

Solve each system of equations by writing a new system that eliminates one of the variables.

Rufina [12.5K]

Answer:

$x=33\\y=-41$

Step-by-step explanation:

Let:

$2x+y=25\hspace{5}(1)\\and\\4x+3y=9\hspace{5}(2)$

We need to eliminate one of the variables, so let's use elimination method. First multiply (1) by 2

$2*(1)\equiv\hspace{5}4x+2y=50$

Now subtract (2) from 2*(1) in order to eliminate x:

$2*(1)-(2)\\4x-4x+2y-3y=50-9\\-y=41$

Solving for y:

Multiplying both sides by -1

$y=-41$

Finally, replacing the value of y in (1)

$2x-41=25$

Solving for x:

add 41 to both sides:

$2x=66$

Multiply both sides by 1/2:

$x=\frac{66}{2} =33$

3 0

2 years ago

Given the function f(x) = x^4 + 3x^3 - 2x^2 - 6x - 1, use intermediate theorem to decide which of the following intervals contai

marta [7]

$f(x) = x^4 + 3x^3 - 2x^2 - 6x - 1$

Lets check with every option

(a) [-4,-3]

We plug in -4 for x and -3 for x

$f(-4) = (-4)^4 + 3(-4)^3 - 2(-4)^2 - 6(-4) - 1= 55$

$f(-3) = (-3)^4 + 3(-3)^3 - 2(-3)^2 - 6(-3) - 1= -1$

f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.

(b) [-3,-2]

We plug in -3 for x and -2 for x

$f(-3) = (-3)^4 + 3(-3)^3 - 2(-3)^2 - 6(-3) - 1= -1$

$f(-2) = (-2)^4 + 3(-2)^3 - 2(-2)^2 - 6(-2) - 1= -5$

f(-2) is negative and f(-3) is negative. there is no value at x=c on the interval [-3,-2] where f(c)=0.

(c) [-2,-1]

We plug in -2 for x and -1 for x

$f(-2) = (-2)^4 + 3(-2)^3 - 2(-2)^2 - 6(-2) - 1= -5$

$f(-1) = (-1)^4 + 3(-1)^3 - 2(-1)^2 - 6(-1) - 1= 1$

f(-2) is negative and f(-1) is positive. there is some value at x=c on the interval [-2,-1] where f(c)=0. so there exists atleast one zero on this interval.

(d) [-1,0]

We plug in -1 for x and 0 for x

$f(-1) = (-1)^4 + 3(-1)^3 - 2(-1)^2 - 6(-1) - 1= 1$

$f(0) = (0)^4 + 3(0)^3 - 2(0)^2 - 6(0) - 1= -1$

f(-1) is positive and f(0) is negative. there is some value at x=c on the interval [-1,0] where f(c)=0. so there exists atleast one zero on this interval.

(e) [0,1]

We plug in 0 for x and 1 for x

$f(0) = (0)^4 + 3(0)^3 - 2(0)^2 - 6(0) - 1= -1$

$f(1) = (1)^4 + 3(1)^3 - 2(1)^2 - 6(1) - 1= -5$

f(0) is negative and f(1) is negative. there is no value at x=c on the interval [0,1] where f(c)=0.

(f) [1,2]

We plug in 1 for x and 2 for x

$f(1) = (1)^4 + 3(1)^3 - 2(1)^2 - 6(1) - 1= -5$

$f(2) = (2)^4 + 3(2)^3 - 2(2)^2 - 6(2) - 1= 19$

f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.

so answers are (a) [-4,-3], (c) [-2,-1], (d) [-1,0], (f) [1,2]

8 0

2 years ago

Read 2 more answers

How do I solve 7√96m^3 ?

aksik [14]

I BELIEVE THAT ALL (96m^3) IS UNDER THE SQUARE ROOT.
If so : 96 could be written as 16x 6 & m³ could be written as m²xm:

7√(96m^3) = 7√(16 x 6 x m² m) =7[4m√(6m)]

=28m√(6m)

4 0

2 years ago

Read 2 more answers