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Lilit [14]
2 years ago
15

The table shows the total number of trees cut down by a logging company over a two-week period. What was the average rate of cha

nge between Day 9 and Day 14?

Mathematics
1 answer:
irina [24]2 years ago
7 0
Average rate of change = slope so lets get our y's and x's and plug them into y2-y1 / x2-x1. (14-9)/(308-195) and that equals 5/113
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PLEASE HURRY ~ NO JOKES, RIGHT ANSWERS ONLY~ WORTH 80 POINTS ~
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The Great Ocean Conveyor Belt

Step-by-step explanation:

The ocean is not a still body of water. There is constant motion in the ocean in the form of a global ocean conveyor belt. This motion is caused by a combination of thermohaline currents (thermo = temperature; haline = salinity) in the deep ocean and wind-driven currents on the surface. Cold, salty water is dense and sinks to the bottom of the ocean while warm water is less dense and remains on the surface.

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Data Set: {60, 30, 35, 30,25}
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Answer:

a. Yes

b. 0.35

c. 0.5

d.

E(x)=34.25

V(x)=73.1875

SD(x)=8.555

Step-by-step explanation:

a.

x      20   25   30      35   40  45 50

f(x) 0.05 0.2 0.25  0.15  0.15 0.1 0.1

This will be valid probability distribution if

1. All probabilities are between 0 and 1 inclusive.

2. Sum of probabilities must be 1.

Condition 1 is satisfied in this distribution. Now, we will check second condition

sum(f(x))=0.05+0.2+0.25+0.15+0.15+0.1+0.1=1.

As the both conditions are satisfied, thus the given distribution is a valid probability distribution.

b.

P(x≥40)=P(X=40)+P(X=45)+P(X=50)

P(x≥40)=0.15+0.1+0.1

P(x≥40)=0.35

So, the probability that Backens and Hayes LLC will obtain 40 or more new clients is 0.35.

c.

P(x<35)=P(X=20)+P(X=25)+P(X=30)

P(x<35)=0.05+0.2+0.25

P(x<35)=0.5

So, the probability that Backens and Hayes LLC will obtain fewer than 35 new clients is 0.5.

d.

Expected value of x=E(x)= sum[x*f(x)]

E(x)= 20*0.05+25*0.2+30*0.25+35*0.15+40*0.15+45*0.1+50*0.1

E(x)=1+5+7.5+5.25+6+4.5+5

E(x)=34.25

Variance of x=V(x)=sum[x²*f(x)]-(sum[x*f(x)])²

sum[x²*f(x)]= 20²*0.05 +25²*0.2 +30²*0.25 +35²*0.15 +40²*0.15 +45²*0.1 +50²*0.1

sum[x²*f(x)]=20+1255+225+183.75+240+202.5+50

sum[x²*f(x)]=1246.25

V(x)=1246.25-(34.25)²

V(x)=73.1875

Standard deviation of x=SD(x)=√V(x)

SD(x)=8.555

3 0
2 years ago
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