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dolphi86 [110]
3 years ago
11

describe the slopes of the parallel lines. Then, give an example of two linear equations that are parallel

Mathematics
1 answer:
Ivan3 years ago
3 0
The slopes are the same.
Example: y=2x+5 & y=2x+7
You might be interested in
Quadrilateral ABCD is inscribed in a circle. Find the measure of each of the angles of the quadrilateral. Show your work.
Xelga [282]
The opposite angles of a quadrilateral are supplementary so you can set them equal to 180.

If there was more information given then i could find the exact values.

Hope this helps :)
8 0
3 years ago
PLEASE HELP ME, MY MOM WILL KILL ME IF I DONT HAVE THEESE ASSIGNMENTS DONE
Schach [20]

Answer:

A. 2

B. 10/3

C. 8/3

D. 2/3

Step-by-step explanation: put the whole #and make it into a fraction like this e.g.

6/1 • 1/3 = 6/3 simplifies to 2

3 0
3 years ago
Write an equation for the line passing through the points (-5,15) and (20,25). Show how you found your answer.
olasank [31]

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-5, 15) and (20, 25). substitute:

m=\dfrac{25-15}{20-(-5)}=\dfrac{10}{25}=\dfrac{2}{5}\\\\y-15=\dfrac{2}{5}(x-(-5))\\\\y-15=\dfrac{2}{5}(x+5)\qquad|\text{use distributive property}\\\\y-15=\dfrac{2}{5}x+2\qquad|\text{add 15 from both sides}\\\\y=\dfrac{2}{5}x+17\qquad|\text{multiply both sides by 5}\\\\5y=2x+85\qquad|\text{subtract 2x from both sides}\\\\-2x+5y=85\qquad|\text{change the signs}\\\\2x-5y=-85

Answer:

point-slope form: y-15=\dfrac{2}{5}(x+5)

slope-intercept form: y=\dfrac{2}{5}x+17

standard form: 2x-5y=-85

7 0
3 years ago
Please Help me!!!
drek231 [11]

Step-by-step explanation:

The displacement of a particle d (in km) as a function of time t (in hours) is given by :

d=2t^3+5t^2-3

Displacement at t = 4 hours,

d(4)=2(4)^3+5(4)^2-3=205\ km

Velocity of particle is given by :

v=\dfrac{dd}{dt}\\\\v=\dfrac{d(2t^3+5t^2-3)}{dt}\\\\v=6t^2+10t

Velocity at t = 4 hours,

v=6(4)^2+10(4)=136\ km/h

Acceleration of the particle is given by :

a=\dfrac{dv}{dt}\\\\a=\dfrac{d(6t^2+10t)}{dt}\\\\a=12t+10

At t = 4 hours,

a=12(4)+10=58\ km/h^2

Therefore, the displacement, velocity and acceleration at t = 4 hours is 205 km, 136 km/h and 58 km/h² respectively.

7 0
3 years ago
What is the angle of C?
soldier1979 [14.2K]

Answer:

50°

Step-by-step explanation:

65 + 65 +C = 180

130+C = 180

C = 180 - 130 = 50

3 0
3 years ago
Read 2 more answers
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