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LUCKY_DIMON [66]
3 years ago
14

A segment has endpoints V and X. What are two names for the segment?

Mathematics
1 answer:
wolverine [178]3 years ago
5 0

Given:

A segment has endpoints V and X.

To find:

The two names for the segment.

Solution:

A line segment is a small part of a line and it has two end points. The name of a segment is described by its end points.

For example: If A and B are two and points of a line segment, then the names for the segment are \overline {AB} and \overline {BA}.

It is given that the segment has endpoints V and X.

Therefore, the two names for the segment are \overline {VX} and \overline {XV}.

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A sundae requires 3 ice-cream scoops and 4 strawberries, and a milkshake requires 2 ice-cream scoops and 6 strawberries. Ramses
drek231 [11]

Answer:

System of inequalities:

3x+2y \leq 25 , 4x+6y \leq 37      

1) Maximum number of sundaes possible = 9

2) Maximum number of milkshakes possible = 6

3) Combination that uses the most of both Ice-cream and Strawberries = 7 scoop of ice-cream and 1 scoop of strawberries.

Step-by-step explanation:

Given : A sundae requires 3 ice-cream scoops and 4 strawberries, and a milkshake requires 2 ice-cream scoops and 6 strawberries.

Ramses wants to make sundaes and milkshakes with at most 25 ice-cream scoops and 37 strawberries.

Let x denote the number of sundaes he makes and y the number of milkshakes he makes.

First we represent in tabular form,

                             Sundae(x)            Milkshake(y)           Total

Ice-cream                  3                           2                         3x+2y

Strawberries             4                            6                         4x+6y

→System of inequalities:

Sundaes and milkshake with at most 25 ice-cream scoops=  3x+2y \leq 25

Sundaes and milkshakes with at most 37 strawberries = 4x+6y \leq 37      

→ Plotting the equations in the graph (figure attached)

1) Maximum number of sundaes possible:

Maximum no. of sundaes possible when y=0

From the graph y=0 at x=9.25

Therefore, Maximum number of sundaes possible is 9

2) Maximum number of milkshakes possible:

Maximum no. of milkshakes  possible when x=0

From the graph x=0 at y= 6.167

Therefore, Maximum number of milkshakes possible is 6

3) Combination that uses the most of both Ice-cream and Strawberries:

Combination of both is possible there is a intersection of both the equation

From the graph intersection point is x=7.6 and y=1.1

Therefore,  Combination that uses the most of both Ice-cream and Strawberries = 7 scoop of ice-cream and 1 scoop of strawberries.


5 0
4 years ago
WILL GIVE BRANLIEST HELP PLEASE!
allochka39001 [22]

I believe since you are looking for the angle of M<ABC, you just add both 120 and 25 together, since they practically share a point.

So 120 + 25 = 145

So I guess 145 would be your answer.

I remembered this type of problem from Geometry.

3 0
3 years ago
Can someone help me with this thanks ​
Firdavs [7]

Answer:

<u><em>i ''Dont Know'' i need more detail on what Ur talking about </em></u>

Step-by-step explanation:

6 0
2 years ago
I have already tryed but how in the world do i solve 2
trapecia [35]
Alright, let's factor this to get the answer.
3k^2-10k+7
To find the factors, we want to think "What will add up to -10, and multiply to (+)7?"
Because the leading coefficient is 3, we know that we can take one factor of 7 and multiply it by 3.
Thus, this factors to
(3k-7)(k-1)
(if you FOIL it it should come out to be the original equation)

From this, set both of those [(3k-7) and (k-1)] equal to zero and solve
3k-7=0
3k=7
/3
k=7/3
or
k=1
6 0
3 years ago
Write the two missing values to make these equivalent fractions correct : ?/3 = 8/12= 4/?
Elodia [21]
X/3 = 8/12
12 * x = 8 * 3
12x = 24
x = 2

8/12 = 4/y
8y = 48
y = 6
8 0
3 years ago
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