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Ksju [112]
3 years ago
10

Which equation is correct

Mathematics
1 answer:
Anika [276]3 years ago
5 0

For this case we have to define trigonometric relations of rectangular triangles that:

  • The cosine of an angle is given by the leg adjacent to the angle on the hypotenuse of the triangle.
  • The sine of an angle is given by the leg opposite the angle on the hypotenuse of the triangle.

Then, according to the figure we have:

Sin (G) = \frac {15} {17}\\Cos (G) = \frac {8} {17}

Answer:

Sin (G) = \frac {15} {17}

Option D

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Urgent help ! similar figures use the similarity relationship to find the indicated value
Oliga [24]

Answer:

my answer is X=3/2 or 1.5

7 0
2 years ago
In the problems below, f(x) = log₂x and
kramer

Answer:

(1,0)

Step-by-step explanation:

The given functions are:

f(x) = log₂x

and

g(x) = log₁₀x

We know that logarithm of 1 is always zero.

This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1

Therefore the point the graphs of f and g have in common is (1,0)

3 0
2 years ago
how do you solve 20 minus 3/4? lol I forgot. I did this back in September, but now we have to do it again. help solve please.
lana66690 [7]
20-3/4= 19 1/4
19 1/4 is your answer.
3 0
3 years ago
Read 2 more answers
Which choices are equivalent to the expression below? Check all that apply. 6√3
Westkost [7]

Answer:

case A. \sqrt{18}*\sqrt{6}

case B. \sqrt{108}

case E. \sqrt{3}*\sqrt{36}

Step-by-step explanation:

we have

6\sqrt{3}

we know that

6\sqrt{3}=\sqrt{36*3}=\sqrt{108}

<u>Verify each case</u>

case A) \sqrt{18}*\sqrt{6}

\sqrt{18}*\sqrt{6}=\sqrt{18*6}=\sqrt{108}

therefore

\sqrt{18}*\sqrt{6} is equivalent to 6\sqrt{3}

case B) \sqrt{108}

so

\sqrt{108} is equivalent to 6\sqrt{3}

case C) \sqrt{3}*\sqrt{6}

\sqrt{3}*\sqrt{6}=\sqrt{18}

therefore

\sqrt{18} is not equivalent to 6\sqrt{3}

case D) \sqrt{54}

so

\sqrt{54} is not equivalent to 6\sqrt{3}

case E) \sqrt{3}*\sqrt{36}

\sqrt{3}*\sqrt{36}=\sqrt{108}

therefore

\sqrt{3}*\sqrt{36} is equivalent to 6\sqrt{3}

case F) 108

so

108 is not equivalent to 6\sqrt{3}

6 0
3 years ago
Tania purchased P packages of pasta for $1.25 each and J jars of sauce for $1.85 each. She purchased 22 items and spent $33.50.
sergey [27]

Answer:

you would need to first do

(p times 1.25)

       +

(j times 1.85)

and then

22 divided by 33.50

Step-by-step explanation:

3 0
3 years ago
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