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matrenka [14]
3 years ago
5

Given: sin = 4/5 and cos x = -5/13 ; evaluate the following expression. Cos 2x

Mathematics
1 answer:
Nitella [24]3 years ago
5 0

For every possible angle x, the fundamental law of trigonometric states that

\sin^2(x)+\cos^2(x) = 1

In your case, the inputs you provided would lead to

\dfrac{16}{25}+\dfrac{25}{169} = \dfrac{3329}{4225} \approx 0.8 \neq 1

So, it is not possible that, for a certain angle x, we have

\sin(x) = \dfrac{4}{5},\quad \cos(x) = -\dfrac{5}{13}

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Answer:

k=40 and -6x3=-12

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Step-by-step explanation:

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3 years ago
100x+300y=1.200<br> (2/3x+10)/100=(y+20)/300
AlexFokin [52]

Answer:

x= -4.284 and y= 1.432

Step-by-step explanation:

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3 years ago
2. What are the measures of
hodyreva [135]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

To answer the above question based on the image, the answer is <span>EBG=45; EBG is acute. EBC=100; EBC is obtuse</span>

6 0
3 years ago
Question: is 1 &gt; 0.99999999...?<br>Prove algebraically.
Crazy boy [7]
No.  We claim that 1=0.\overline{9} and use algebra to prove the statement.

Let x=0.\overline{9}.  Multiply this by ten to get 10x=9.\overline{9}.  Subtract the initial equation to give 9x=9 and divide by 9 to see that x=1.  Substituting into the original equation gives 1=0.\overline{9}, proving the desired statement.
6 0
3 years ago
1. The most massive planet in the solar system, Jupiter, has a mass of about 1,898,000,000,000,000,000,000,000,000 kg. Estimate
UNO [17]

Answer:

D. 2*10^{27} kg

Step-by-step explanation:

Mass of Jupiter is given as 1,898,000,000,000,000,000,000,000,000 kg

Estimating this to the nearest whole number would be = 2,000,000,000,000,000,000,000,000,000 kg (rounding up the the "1,898")

To express this in scientific notation form, simply count how many zeros we have to the nearest whole number, 2.

We have 27 zeros there.

Therefore, we would multiply the whole number, 2, by 10 raise to the power of 27.

An estimate of the mass of Jupiter = 2*10^{27} kg

6 0
3 years ago
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