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erik [133]
3 years ago
6

PLS HELP!! Write the expression as a single logarithm. 3logbq + 6logbv

Mathematics
1 answer:
Alika [10]3 years ago
5 0

\bf \textit{logarithm of factors} \\\\ log_a(xy)\implies log_a(x)+log_a(y) \\\\\\ \textit{Logarithm of exponentials} \\\\ log_a\left( x^b \right)\implies   b\cdot log_a(x) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 3log_b(q)+6log_b(v)\implies log_b(q^3)+log_b(v^6)\implies log_b(q^3v^6)

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You and three friends are going to the fair. The cost for
lions [1.4K]

Answer:

$17 on food per person

Step-by-step explanation:

The cost of parking a car is $5

Assuming that the friends used one car, then the parking cost=$5

Admission cost is 19

For three people, Admission cost =19*3=57

TOTAl COSTS=Parking cost+Admission cost

TOTAl COSTS=57+5=62

Remaining amount can be used for food

FOOD= 113-62=51

Therefore each person can spend 51/3=$17 on food

I hope this was helpful and clear to follow

3 0
2 years ago
Read 2 more answers
Help me with this pls and ty
Bingel [31]

Answer:

It is the second answer.

Step-by-step explanation:

When numbers with the same base are multiplied, you add the bases.

1/2 + 3/4 is the same as

2/4 + 3/4 = 5/4

So now we have 2 ^5/4^2.  When we have a power raised to a power.  We multiply the powers.

5/4(2)

(5/4(2/1) = 10/4 = 5/2.  The second answer is the same way to describe

2^(5/2)

7 0
2 years ago
I'm stuck on this please help!!
kvv77 [185]
The answer is D
\frac{12 {x}^{6}  {y}^{ - 4} {z}^{2}  }{3 {x}^{2}  {y}^{ - 6}  {z}^{3} } \\  =  \frac{4 {x}^{4}  {y}^{2} }{z}
5 0
3 years ago
What number is not in the domain of x+6/x-7
Aleksandr [31]

Answer:

x= -11

Step-by-step explanation:

3 0
2 years ago
Whats the property? If -7x=14 then 14=-7x
timofeeve [1]

Answer:

the answer is commutative property

Step-by-step explanation:

commutative property is when both constants or variables don't change value when you move them from one side of the equal sign to another such as "a+b = b+a" or " a=b; b=a" both examples do not change value

3 0
3 years ago
Read 2 more answers
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