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erik [133]
3 years ago
6

PLS HELP!! Write the expression as a single logarithm. 3logbq + 6logbv

Mathematics
1 answer:
Alika [10]3 years ago
5 0

\bf \textit{logarithm of factors} \\\\ log_a(xy)\implies log_a(x)+log_a(y) \\\\\\ \textit{Logarithm of exponentials} \\\\ log_a\left( x^b \right)\implies   b\cdot log_a(x) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 3log_b(q)+6log_b(v)\implies log_b(q^3)+log_b(v^6)\implies log_b(q^3v^6)

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What is the midpoint of the vertical line segment graphed below? (2, 4), (2, -9) A. (4, -5). B. (2, -5/2). C. (2, -5). D. (4, 5/
omeli [17]

Answer:

B. (2, -\frac{5}{2})

Step-by-step explanation:

Given:

(2, 4) and (2, -9)

Required:

Midpoint of the vertical line with the above endpoints

Solution:

Apply the midpoint formula, which is:

M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})

Where,

(2, 4) = (x_1, y_1)

(2, -9) = (x_2, y_2)

Plug in the values into the equation:

M(\frac{2 + 2}{2}, \frac{4 + (-9)}{2})

M(\frac{4}{2}, \frac{-5}{2})

M(2, -\frac{5}{2})

8 0
2 years ago
How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution.
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The answer is B

15 L of pure water must be mixed with 10 L of a 25% acid solution to reduce it to a 10% acid solution
3 0
3 years ago
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ASAAPPP!! Which of the following exponential equations could be represented by the table below?
Ne4ueva [31]

Answer:

Option C

Step-by-step explanation:

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3 years ago
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What is the answer of <br> reciprocal of 1/7
serg [7]
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What is the simplified form of √10000x^64 ? 5000x^32 5000x^8 100x^8 100x^32
denis23 [38]

Answer:

Option (d) is correct.

\sqrt{10000x^{64}}=100x^{32}

Step-by-step explanation:

Given : Expression \sqrt{10000x^{64}}

We have to write a simplified form of the given expression \sqrt{10000x^{64}}

Consider the given expression \sqrt{10000x^{64}}

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0

=\sqrt{10000}\sqrt{x^{64}}

Factor 10000 as 10000=100^2

\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a

\sqrt{100^2}=100

also, \mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^m}=a^{\frac{m}{n}},\:\quad \mathrm{\:assuming\:}a\ge 0

We have,

\sqrt{x^{64}}=x^{\frac{64}{2}}=x^{32}

Thus, \sqrt{10000x^{64}}=100x^{32}

8 0
3 years ago
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