Question

PLS HELP!! Write the expression as a single logarithm. 3logbq + 6logbv

Answer 1

$\bf \textit{logarithm of factors} \\\\ log_a(xy)\implies log_a(x)+log_a(y) \\\\\\ \textit{Logarithm of exponentials} \\\\ log_a\left( x^b \right)\implies b\cdot log_a(x) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 3log_b(q)+6log_b(v)\implies log_b(q^3)+log_b(v^6)\implies log_b(q^3v^6)$