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erik [133]
3 years ago
6

PLS HELP!! Write the expression as a single logarithm. 3logbq + 6logbv

Mathematics
1 answer:
Alika [10]3 years ago
5 0

\bf \textit{logarithm of factors} \\\\ log_a(xy)\implies log_a(x)+log_a(y) \\\\\\ \textit{Logarithm of exponentials} \\\\ log_a\left( x^b \right)\implies   b\cdot log_a(x) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 3log_b(q)+6log_b(v)\implies log_b(q^3)+log_b(v^6)\implies log_b(q^3v^6)

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Answer:

a) curva denominada parábola com vértice voltado pra baixo

Step-by-step explanation:

espero que esto ayude

No sé si es del todo correcto, ¡pero que tengas un buen día!

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Vitek1552 [10]

Answer:

  b.  4x^2 + 3x - 6

Step-by-step explanation:

The values of f(x) for the extremes of x are more positive than the value of f(x) for the middle x, so we know the parabola opens upward. That eliminates choice D.

It is probably easiest to evaluate the other expressions to see which one matches the given f(x) values. For the purpose, it is usually easier to use the Horner form of the equation.

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8 0
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Hope this Helps!!!

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