Answer:
53.57%
Step-by-step explanation:
We have to calculate first the specific number of events that interest us, if at least 3 are girls, they mean that 2 are boys, therefore we must find the combinations of 3 girls of 5 and 2 boys of 3, and multiply that, so :
# of ways to succeed = 5C3 * 3C2 = 5! / (3! * (5-3)!) * 3! / (2! * (3-2)!)
= 10 * 3 = 30
That is, there are 30 favorable cases, now we must calculate the total number of options, which would be the combination of 5 people from the group of 8.
# of random groups of 5 = 8C5 = 8! / (5! * (8-5)!) = 56
That is to say, in total there are 56 ways, the probability would be the quotient of these two numbers like this:
P (3 girls and 2 boys) = 30/56 = 0.5357
Which means that the probability is 53.57%
First move the terms to get
6m-m=13+2
Then collect the like terms and calculate the sum, 5m=15
Divide both sides by 5
And you get m=3
Given :
Two equations :
-8x + 3y = -17 ....1)
3x - y = 7 ....2)
To Find :
The solution of the system.
Solution :
Multiplying equation 2) by 3 and adding with equation 1), we get :
(-8x + 3y) + 3(3x - y) = -17 + 21
x = 4
Putting above value of x equation 2) we get :
12 - y = 7
y = 5
Therefore, solution of system is ( 4,5 ).
