Let the one type of the bread be bread A
The second type of the bread be bread B
Let the flour be 'f' and the butter be 'b'
We need 150f + 50b for bread A and 75f + 75b for bread B
We can compare the amount of flour and bread needed for each bread and write them as ratio
FLOUR
Bread A : Bread B
150 : 75
2 : 1
We have a total of 2250gr of flour, and this amount is to be divided into the ratio of 2 parts : 1 part. There is a total of 3 parts.
2250 ÷ 3 = 750 gr for one part then multiply back into the ratio to get
Bread A : Bread B = (2×750) : (1×750) = 1500 : 750
BUTTER
Bread A : Bread B = 50 : 75 = 2 : 3
The amount of butter available, 1250 gr is to be divided into 2 parts : 3 parts.
There are 5 parts in total
1250 ÷ 5 = 250 gr for one part, then multiply this back into the ratio
Bread A: Bread B = (2×250) : (3×250) = 500 : 750
Hence, for bread A we need 1500 gr of flour and 500 gr of butter, and for bread B, we need 750 gr of flour and 750 gr of butter.
The constants, -3 and -8, are like terms
The terms 3p and p are like terms
The terms in the expression are p^2, -3, 3p, -8, p, p^3
The expression contains 6 terms.
Like terms have the same variables raised to the same powers.
P(x) = 4x + 1550 <== ur function
selling only 50 copies...
P(50) = 4(50) + 1550
P(50) = 200 + 1550
P(50) = 1750....so the printing cost for 50 copies is 1750
1750 = 50x....x = cost of each book
1750/50 = x
35 = x.......u would have to sell each book for $ 35 <===
Reggie’s speed = distance/time
Reggie’s speed = 40.2 / 2.5
Reggie’s speed = 16.08 mi/hr
Craig’s speed = distance/time
Craig’s speed = 30.8 / 1.875
Craig’s speed = 16.43 mi/hr
Hence, answer is Craig
