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scoray [572]
3 years ago
9

Use the identity below to complete the tasks:

Mathematics
2 answers:
quester [9]3 years ago
7 0

Answer:

a=[2q^{2}r]

b=[3s^{2}t]

Step-by-step explanation:

we have

8q^{6}r^{3}+27s^{6}t^{3}

we know that

8q^{6}r^{3}=(2^{3})(q^{2})^{3}r^{3}=[2q^{2}r]^{3}

27s^{6}t^{3}=(3^{3})(s^{2})^{3}t^{3}=[3s^{2}t]^{3}

therefore

a=[2q^{2}r]

b=[3s^{2}t]

substitute

a^{3} +b^{3}=(a+b)(a^{2} -ab+b^{2})

[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([2q^{2}r]^{2} -[2q^{2}r][3s^{2}t]+[3s^{2}t]^{2})

[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([4q^{4}r^{2}] -6[q^{2}r][s^{2}t]+[9s^{4}t^{2}])

maw [93]3 years ago
7 0

Answer:

a= 2q^2r

b=3s^t

Step-by-step explanation:

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<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is x^{3}-2 x^{2}-x+2=0

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

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Substitute the above values in f(x)

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Step-by-step explanation:

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