Step-by-step explanation:
Given function is y = –x.
Substitute the values of x in the function and find the values of y.
y = –x
At x = –2,
y = –(–2) = 2
At x = –1,
y = –(–1) = 1
At x = 0,
y = –(0) = 0
At x = 1,
y = –1(1) = –1
At x = 2,
y = –(2) = –2
Now, substitute the values of y in the table.
The image of the table is attached below.
8m+27= 2m-3
take 2m and subtract it from 8m, this gives you 6m. now your equation is 6m+27=-3.
subtract 27 from -3, this will make it 6m=-30.
divide 30 by 6. this gives you your answer. m=-5, because -30 divided by 6 equals -5.
now to test it you can plug -5 into the equation in place of M. 8 times -5 equals -40, plus 27 equals -13. 2 times -5 equals -10 plus -3 equals -13.
Answer:
The probability that the aircraft is overload = 0.9999
Yes , The pilot has to be take strict action .
Step-by-step explanation:
P.S - The exact question is -
Given - Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.
To find - What is the probability that the aircraft is overloaded ?
Should the pilot take any action to correct for an overloaded aircraft ?
Proof -
Given that,
Mean, μ = 182.7
Standard Deviation, σ = 39.6
Now,
Let X be the Weight of the men
Now,
Probability that the aircraft is loaded be
P(X > 168 ) = P( )
= P( z > )
= P( z > -0.371)
= 1 - P ( z ≤ -0.371 )
= 1 - P( z > 0.371)
= 1 - 0.00010363
= 0.9999
⇒P(X > 168) = 0.9999
As the probability of weight overload = 0.9999
So, The pilot has to be take strict action .
Answer:10%
Step-by-step explanation: