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xxMikexx [17]
3 years ago
7

Find the image of (-1,3) obtained by translating 2 units down, followed by a rotation of 270 degrees counterclockwise about the

origin
Mathematics
1 answer:
kiruha [24]3 years ago
7 0

Answer:

[1, 1]

Step-by-step explanation:

Translation → [-1, 3] moves down to [-1, 1]

Now, a <em>90°-clockwise rotation</em> is the exact same as a <em>270°-counterclockwise rotation</em>, and according to the <em>270°-counterclockwise rotation</em> [<em>90°-clockwise rotation</em>] rule, you take the y-coordinate, bring it over to your new x-coordinate, and take the OPPOSITE of the x-coordinate and set it as your new y-coordinate:

<u>Extended Rotation Rules</u>

  • 270°-clockwise rotation [90°-counterclockwise rotation] >> (<em>x, y</em>) → (<em>-y, x</em>)
  • 270°-counterclockwise rotation [90°-clockwise rotation] >> (<em>x, y</em>) → (<em>y, -x</em>)
  • 180°-rotation >> (<em>x, y</em>) → (<em>-x, -y</em>)

Then, you perform your rotation:

270°-counterclockwise rotation [90°-clockwise rotation] → [-1, 1] moves to [1, 1]

I am joyous to assist you anytime.

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Based on the model ​N(11541154​,8686​) describing steer​ weights, what are the cutoff values for ​a) the highest​ 10% of the​ we
yaroslaw [1]

Answer:

a) x = 1225.68

b) x = 1081.76

c)  1109.28 < x < 1198.72

Step-by-step explanation:

Given:

- Th random variable X for steer weight follows a normal distribution:

                                    X~ N( 1154 , 86 )

Find:

a) the highest​ 10% of the​ weights? ​

b) the lowest​ 20% of the​ weights? ​

c) the middle​ 40% of the​ weights? ​

Solution:

a)

We will compute the corresponding Z-value for highest cut off 10%:

                                   Z @ 0.10 = 1.28

                                    Z = (x-u) / sd

Where,

u: Mean of the distribution.

s.d: Standard deviation of the distribution.

                                   1.28 = (x - 1154) / 86

                                      x = 1.28*86 + 1154

                                      x = 1225.68

b)

We will compute the corresponding Z-value for lowest cut off 20%:

                                   -Z @ 0.20 = -0.84

                                    Z = (x-u) / sd

                                   -0.84 = (x - 1154) / 86

                                      x = -0.84*86 + 1154

                                      x = 1081.76

c)

We will compute the corresponding Z-value for middle cut off 40%:

                                    Z @ 0.3 = -0.52

                                    Z @ 0.7 = 0.52

                                    [email protected] < x < [email protected]

                       -.52*86 + 1154 < x < 0.52*86 + 1154

                                  1109.28 < x < 1198.72

7 0
3 years ago
Please help!!
vitfil [10]

Answer:

Step-by-step explanation:

Question says that it uses 120 feet of fencing material to enclose three sides of the play area. This means there are 3 sides. Putting this into equation, we have something like this.

120 = L + 2W

Where

LW = area.

Again, in order to maximize the area with the given fencing, from the equation written above, then Width, w must be = 30 feet and length, l must be = 60

On substituting, we have

A = LW = (120 - 2W) W

From the first equation, making L the subject of the formula, we have this

L = 120 - 2W, which then we substituted above.

On simplification, we have

L = 120W -2W²

Differentiating, we have

A' = 120 - 4W = 0

Remember that W = 30

So therefore, L = 120 - 2(30) = 60 feet

4 0
2 years ago
Selected-Response
guajiro [1.7K]
You have to figure out how many 32 ounces are in 96. the answer to that is 3. you then multiply 2 pints times 3 to get 6.

answer is d.) 6 pints
5 0
3 years ago
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Please this is a test I need to show work to so please explain
Ratling [72]
Explain what? where’s the question dude
7 0
3 years ago
An installation technician for a specialized communication system is dispatched to a city only when 3 or more orders have been p
bazaltina [42]

Answer:

0.3233

0.09

Step-by-step explanation:

Given that :

Mean, λ = 0.25 for a 100,000 per week

For a population of 800,000 :

λ = 800,000 / 100,000 * 0.25 = 8 * 0.25 = 2 orders per week

Probability that technician is required after one week ;

After one week, order is beyond 2 ; hence, order, x ≥ 3

P(x ≥ 3) = 1 - [p(x=0) + p(x= 1) + p(x =2)]

P(x ≥ 3) = 1 - e^-λ(1 + 2¹/1! + 2²/2!)

P(x ≥ 3) = 1 - e^-2(1+2+2) = 1 - e^-2*5 = 1 - e^-10

P(x ≥ 3) = 1 - e^-2 * 10

P(x ≥ 3) = 1 - 0.6766764

P(x ≥ 3) = 0.3233

B.)

Mean, λ for more than 2 weeks = 2 * 2 = 4

P(x < 2) = p(x = 0) + p(x = 1)

P(x < 2) = e^-4(0 + 4^1/1!)

P(x < 2) = e^-4(0 + 4) = e^-4(5)

P(x < 2) = e^-4(5) = 0.0183156 * 5 = 0.0915

P(x < 2) = 0.09

8 0
3 years ago
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