Answer:
-3,2
Step-by-step explanation:
Given:
A figure of a circle. A secant SU and a tangent SR is drawn to the circle from the external point S.
To find:
The measure of the line segment TU.
Solution:
According to the secant tangent segment theorem, the square of tangent is equal to the product of secant and external segment of the secant.
Using secant tangent segment theorem, we get
![SR^2=SU\times ST](https://tex.z-dn.net/?f=SR%5E2%3DSU%5Ctimes%20ST)
![(40)^2=(32+2x-2)\times (32)](https://tex.z-dn.net/?f=%2840%29%5E2%3D%2832%2B2x-2%29%5Ctimes%20%2832%29)
![1600=(30+2x)(32)](https://tex.z-dn.net/?f=1600%3D%2830%2B2x%29%2832%29)
![1600=960+64x](https://tex.z-dn.net/?f=1600%3D960%2B64x)
Subtract both sides by 960.
![1600-960=64x](https://tex.z-dn.net/?f=1600-960%3D64x)
![640=64x](https://tex.z-dn.net/?f=640%3D64x)
Divide both sides by 64.
![\dfrac{640}{64}=x](https://tex.z-dn.net/?f=%5Cdfrac%7B640%7D%7B64%7D%3Dx)
![10=x](https://tex.z-dn.net/?f=10%3Dx)
Now, the measure of the line segment TU is:
![TU=2x-2](https://tex.z-dn.net/?f=TU%3D2x-2)
![TU=2(10)-2](https://tex.z-dn.net/?f=TU%3D2%2810%29-2)
![TU=20-2](https://tex.z-dn.net/?f=TU%3D20-2)
![TU=18](https://tex.z-dn.net/?f=TU%3D18)
Therefore, the correct option is C.
Answer: 615
Step-by-step explanation: you take the 45 times 12 months plus the 75 for the one time fee.
Answer:
sec x = √10 /3
Step-by-step explanation:
tanx = 1/3
tan²x = (1/3)²
= 1/9
Trigonometric identity
sec²x - tan²x = 1
sec²x = 1 + tan²x
sec²x = 1 + 1/9
= 10/9
Now, sec x = √(10/9)
= √10 / 3
Hope this answer helps you....