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shepuryov [24]
3 years ago
11

10 POINTS!! Find x. Assume that any segment that appears to be tangent is tangent.

Mathematics
1 answer:
Mice21 [21]3 years ago
7 0

Answer:

10

Step-by-step explanation:

130+40+x =180

x=10

option 2 is correct

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Dilation because the sides will not be the same size as the original
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PLEASE HELP!!!!!!!!!!
yan [13]

115 = l \times 2.5 \times 5.75

\huge \mathrm{Answer࿐}

given :

\longmapsto volume = 115 yd³

Dimensions are :

  • 2\frac{1}{2} yd

  • 5\frac{3}{4} yd

  • L

We know,

\large \boxed{ \mathrm{volume = l \times b \times h}}

  • 115 =  2\frac{1}{2}  \times  5\frac{3}{4}  \times l

  • l \times  \dfrac{5}{2}  \times  \dfrac{23}{4}  = 115

  • l  \times  \dfrac{115}{8} = 115

  • l = 115 \times  \dfrac{8}{115}

  • l = 8 \: yd

Therefore Length of the prism is 8 yards.

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5 0
3 years ago
ABCD is a parallelogram. Find the measure of angle ABC.​
iVinArrow [24]

Answer:

∠ABC = 50°

Step-by-step explanation:

Since this is a parallelogram, opposite angles are congruent.

Therefore, ∠D ≅ ∠B

∠D = 38° + 12°

∠B = 38° + 12°

∠B = 50°

∠ABC = 50°

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8x -6=18 what does x equal
professor190 [17]

Answer:

x = 3

Step-by-step explanation:

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Add 6 to both sides.

8x = 24

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4 0
2 years ago
What is the smallest integer $n$, greater than $1$, such that $n^{-1}\pmod{130}$ and $n^{-1}\pmod{231}$ are both defined?
olasank [31]

First of all, the modular inverse of n modulo k can only exist if GCD(n, k) = 1.

We have

130 = 2 • 5 • 13

231 = 3 • 7 • 11

so n must be free of 2, 3, 5, 7, 11, and 13, which are the first six primes. It follows that n = 17 must the least integer that satisfies the conditions.

To verify the claim, we try to solve the system of congruences

\begin{cases} 17x \equiv 1 \pmod{130} \\ 17y \equiv 1 \pmod{231} \end{cases}

Use the Euclidean algorithm to express 1 as a linear combination of 130 and 17:

130 = 7 • 17 + 11

17 = 1 • 11 + 6

11 = 1 • 6 + 5

6 = 1 • 5 + 1

⇒   1 = 23 • 17 - 3 • 130

Then

23 • 17 - 3 • 130 ≡ 23 • 17 ≡ 1 (mod 130)

so that x = 23.

Repeat for 231 and 17:

231 = 13 • 17 + 10

17 = 1 • 10 + 7

10 = 1 • 7 + 3

7 = 2 • 3 + 1

⇒   1 = 68 • 17 - 5 • 231

Then

68 • 17 - 5 • 231 ≡ = 68 • 17 ≡ 1 (mod 231)

so that y = 68.

3 0
3 years ago
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