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ryzh [129]
3 years ago
6

HELP ASAP WITH DOMAIN AND RAGE. WILL GIVE BRAINLIEST!

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
8 0

Answer:

the domain is greater than or equal to 75 range is greater than or equal to 40

Step-by-step explanation:

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A gas can holds 10 liters of gas. How many cans could we fill with 35 liters of gas?cans
Ronch [10]

Answer:

7/10

Step-by-step explanation:

We need to divide the 7 liters by the 10 liters that each can holds.

4 0
3 years ago
What is “One third of the opposite of a number is less than 12?”
nirvana33 [79]

Answer:

\frac{1}{3}(-x)<12

4 0
3 years ago
he number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.02
Yakvenalex [24]

Answer:

a) 98.01%

b) 13.53\%

c) 27.06%

Step-by-step explanation:

Since a car has 10 square feet of plastic panel, the expected value (mean) for a car to have one flaw is 10*0.02 = 0.2  

If we call P(k) the probability that a car has k flaws then, as P follows a Poisson distribution with mean 0.2,

P(k)= \frac{0.2^ke^{-0.2}}{k!}

a)

In this case, we are looking for P(0)

P(0)= \frac{0.2^0e^{-0.2}}{0!}=e^{-0.2}=0.9801=98.01\%

So, the probability that a car has no flaws is 98.01%

b)

Ten cars have 100 square feet of plastic panel, so now the mean is 100*0.02 = 2 flaws every ten cars.

Now P(k) is the probability that 10 cars have k flaws and  

P(k)= \frac{2^ke^{-2}}{k!}

and  

P(0)= \frac{2^0e^{-2}}{0!}=0.1353=13.53\%

And the probability that 10 cars have no flaws is 13.53%

c)

Here, we are looking for P(1) with P defined as in b)

P(1)= \frac{2^1e^{-2}}{1!}=2e^{-2}=0.2706=27.06\%

Hence, the probability that at most one car has no flaws is 27.06%

6 0
3 years ago
Read 2 more answers
Fing the value of x, -3(2x-9)=3(16-x)
Ksivusya [100]

Answer:

x= -7

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
This is important please help
Leya [2.2K]

Answer: C

<u>Step-by-step explanation:</u>

∑ 8(\frac{7}{3})⁽ⁿ⁻¹⁾ from n = 1 to n = 5

n = 1 → 8(\frac{7}{3})⁽¹⁻¹⁾

        = 8                                         = \frac{648}{81}

n = 2 → 8(\frac{7}{3})⁽²⁻¹⁾

         = \frac{56}{3}                                         = \frac{1512}{81}    

n = 3 → 8(\frac{7}{3})⁽³⁻¹⁾

          = \frac{392}{9}                                     = \frac{3528}{81}

n = 4 → 8(\frac{7}{3})⁽⁴⁻¹⁾

          = \frac{2744}{27}                                 = \frac{8232}{81}

n = 5 → 8(\frac{7}{3})⁽⁵⁻¹⁾

          = \frac{19208}{81}                                = \frac{19208}{81}

                                                                            Sum = \frac{33128}{81}

                                                                                    = 408.99

     

6 0
3 years ago
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