Given the polynomial function

If (x-3) is a factor of P(x), then

, for some polynomial Q of 1st degree,
Then according to the factor theorem P(3)=0, because P(3)=(3-3)Q(x)=0*Q(3)=0.
Check

≠0
we see that P(3) is not 0, so (x-3) is not a factor of P(x).
Answer: no
Answer:
-3 >v
Step-by-step explanation:
3v-37>-2(8-5v)
Distribute
3v -37> -16 + 10v
Subtract 3 from each side
3v -3v -37> -16 + 10v-3v
-37 > -16 +7v
Add 16 to each side
-37 +16 > -16+16 +7v
-21 > 7v
Divide each side by 7
-21/7 >7v/7
-3 >v
Answer:
1 1\3
Step-by-step explanation:
4\3 = 1\3
your welcome
Answer:
I am pretty sure it is 14.875
Step-by-step explanation: