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eduard
3 years ago
10

A 99% confidence interval for the sugar content (per 5 oz. serving) of a shipment of strawberries is 5.9 to 8.3 grams.

Mathematics
1 answer:
gavmur [86]3 years ago
5 0

Answer:

Sample mean = 7.1

Margin of error = 0.465

Step-by-step explanation:

Formula for confidence interval is;

CI = x¯ ± zE

Where;

x¯ is sample mean

z is critical value at confidence level

E is margin of error.

z for 99% Cl is 2.58

We are told the CI is 5.9 to 8.3.

Thus;

5.9 = x¯ - 2.58E - - - - (1)

8.3 = x¯ + 2.58E - - - - (2)

Add both equations together to get;

14.2 = 2x¯

x¯ = 14.2/2

x¯ = 7.1

Put 7.1 for x¯ in eq 1 to get;

5.9 = 7.1 - 2.58E

7.1 - 5.9 = 2.58E

E = 1.2/2.58

E = 0.465

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lukranit [14]
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6 0
3 years ago
Which list is in order from least to greatest? A) 9.4 * 10^-8, 9.25 * 10^-6, 2.5 * 10^3, 7* 10^3 B) 2.5 *10^3, 7 * 10^3, 9.25 *
vladimir1956 [14]

ANSWER

A) 9.4 * 10^-8, 9.25 * 10^-6, 2.5 * 10^3, 7* 10^3

EXPLANATION

The numbers are given in standard form.

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The bigger the exponents the bigger the number.

The second criteria is that, if the exponents of any two numbers are the same, then we use the numbers multiplying the powers of 10 to order.

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6 0
4 years ago
Read 2 more answers
Order the following numbers from least to greatest.<br>5/4<br>1 8/25<br>1.3​
Lubov Fominskaja [6]

Answer:

18/25,  5/4, 1.3

Step-by-step explanation:

What you need to do is to divide each fraction so that you can change to a number.

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7 0
3 years ago
What is the total finance charge for a $4,250 loan at 13.25% interest compounded monthly for 24 months?
Rom4ik [11]
Since only the principal value, interest rate and interest period are given, we can deduce that "finance charge" only includes the interest to be paid at the end of the term. This can be obtained by subtracting the principal value from the future value which we will solve for.

The future value can be solved by using the following compound interest formula:

Let:
F = Future value
P = Principal value
r<span> = annual interest rate </span>
n<span> = number of times that interest is compounded per year</span>
t<span> = number of years</span>

F = P(1 + r/n)^nt

Substituting the given values:
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Subtracting P from F:
Finance charge = 5531.54 - 4250 = 1281.54

Therefore the finance charge is $1,281.54
6 0
3 years ago
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