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ANTONII [103]
3 years ago
15

5 3/8 - 2 1/8 = (make sure you simplify the fraction)

Mathematics
1 answer:
Alex787 [66]3 years ago
6 0
13/4, is your answer.
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a. Determine whether the Mean Value Theorem applies to the function f (x )equals ln 15 xf(x)=ln15x on the given interval [1 comm
ivolga24 [154]

Answer:

(a)

The function f is continuous at [1,e] and differentiable at (1,e), therefore

the mean value theorem applies to the function.

(b)

c = e-1 \\ = 1.71828

Step-by-step explanation:

(a)

The function f is continuous at [1,e] and differentiable at (1,e), therefore

the mean value theorem applies to the function.

(b)

You are looking for a point c   such that

\frac{1}{c} = \frac{\ln(15e)-\ln(15*1)}{e-1} = \frac{\ln(15e/15)}{e-1} = \frac{\ln(e)}{e-1} = \frac{1}{e-1}

You have to solve for c  and get that

c = e-1 \\ = 1.71828

5 0
3 years ago
How much carbon dioxide is emitted from using a 1500 watt dryer for 8 hours every
slavikrds [6]

ERROR!ERROR!ERROR!ERROR!

5 0
3 years ago
Read 2 more answers
PLEASE HELP!! I worked it out and haven’t found the right answer
8_murik_8 [283]

Answer:

option B is correct. Once have a look to this solution that I have answered

5 0
3 years ago
John jogs 2 7/10 miles to the park. Marsha jogs 4/5 miles to the park. How much farther does John jog?
Elden [556K]

Answer:

1.9 miles.

Step-by-step explanation:

John jogs 2 7/10 miles to the park. Marsha jogs 4/5 miles to the park.

Convert the fractions into decimals:

2 7/10 = 2.7

4/5 = 0.8

Subtract '0.8' from '2.7':

2.7-0.8=1.9

John should jog 1.9 miles farther than Marsha.

Hope this helps.

7 0
3 years ago
Read 2 more answers
Please answer this correctly without making mistakes
victus00 [196]

Answer:

Question 2

Step-by-step explanation:

2) The time when she woke up was -  3° C

During nature walk, temperature got 3° C warmer than when she woke up.

So, temperature during nature walk = - 3 + 3 = 0° C

3 0
3 years ago
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