William is taking the 25-question, multiple choice American Mathematics Competition. Each question has five answer choices. Will
1 answer:
Given that <span>William guesses random answers for the last four questions and that e</span><span>ach question has five answer choices.</span><span>
The probability that he gets an answer correct </span>is 1 / 5.
The probability that he did not get an answer correct is 4 / 5.
The probability that he will not get any of the 4 questions correctly is
Therefore, the probability that he gets at least one of the 4 questions correctly is
The probability that he gets an answer correct </span>is 1 / 5.
The probability that he did not get an answer correct is 4 / 5.
The probability that he will not get any of the 4 questions correctly is
Therefore, the probability that he gets at least one of the 4 questions correctly is
You might be interested in
Answer:
8 different combinations are possible.
Step-by-step explanation:
Here, we have 2 different combinations for each time.
And the player comes out to bat 3 times.
So, total number of combinations are:
i.e. a total of 8 number of times.
Let a hit is termed as 'H' and an out is termed as 'O'.
Total combinations are:
{HHH, HHO, HOH, HOO, OHH, OHO, OOH, OOO}
Kindly have a look at the tree diagram attached in the answer area.
In starting, there are 2 combinations possible, i.e. 'O' and 'H'.
After 'O' , 2 possible i.e. 'O' and 'H'.
After 'H' , 2 possible i.e. 'O' and 'H'.
and so on....
