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pentagon [3]
4 years ago
11

Gasoline is that distillation fraction that has a boiling point range of

Mathematics
2 answers:
strojnjashka [21]4 years ago
5 0

Answer:

Gasoline is a petroleum-derived product comprising a mixture of liquid aliphatic and aromatic hydrocarbons, ranging between C4 and C12 carbon atoms with the boiling range of 30–225°C. It is predominantly a mixture of paraffins, naphthenes, aromatics and olefins. hope that helps love!

frez [133]4 years ago
3 0

Answer:

Answer is below

Step-by-step explanation:

Gasoline has an initial boiling point at about 35 °C or 95 °F and a final boiling point of about 200 °C or 395 °F.

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3 out of 5 picks are orange. if 12 picks are orange haw many picks are in all
xxTIMURxx [149]

Answer:

There were 20 picks total

Step-by-step explanation:

We can use a proportion to solve this problem.  Put the orange picks on top and the total picks on bottom

3 orange         12 orange

-------------- =   ---------------

5 total                x total

Using cross products

3x = 5*12

3x= 60

Divide each side by 3

3x/3 = 60/3

x = 20

There were 20 picks total

7 0
3 years ago
Read 2 more answers
Which expression has a value of 18 when n=7?
Lorico [155]
Hello There!

I'm sure it is B. 6n - 24

Hope This Helps You!
Good Luck :) 

- Hannah ❤
8 0
3 years ago
Read 2 more answers
A triangle has vertices at (-2,-3),(4, -3), and (3,5). What is the area of the triangle?
Bezzdna [24]

Answer:

this triangle is ABC with A(-2 ; -3), B(4; - 3) and C(3;5)

=> AB=\sqrt{(4-(-2))^{2}+\sqrt{(-3 -(-3))^{2} }  }=\sqrt{6^{2} }=6\\\\AC=\sqrt{(3-(-2))^{2}+(5-(-3))^{2}  }=\sqrt{5^{2}+8^{2}  }=\sqrt{89}\\\\BC =\sqrt{1^{2}+8^{2}  }=\sqrt{65}

using Heron theorem, we have:

S=\sqrt{p(p-AB)(p-AC)(p-BC)}\\\\S=\sqrt{(\frac{6+\sqrt{89}+\sqrt{65} }{2})(\frac{\sqrt{89}+\sqrt{65}-6  }{2} )(\frac{6+\sqrt{65}-\sqrt{89}  }{2})(\frac{6+\sqrt{89}-\sqrt{65}  }{2})   }\\\\S=24  \\\\

with S is the area of the triangle

       p=\frac{AB+AC+BC}{2}=\frac{6+\sqrt{89}+\sqrt{65}  }{2}

Step-by-step explanation:

5 0
3 years ago
A random variable is not normally distributed, but it is mound shaped. It has a mean of 11 and a standard deviation of 4.
mariarad [96]

Using the Central Limit Theorem, nothing can be stated about the shape of the sampling distribution for the sample mean, as the sample size is less than 30.

<h3>What does the Central Limit Theorem state?</h3>

It states that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the sampling distribution is also approximately normal, as long as n is at least 30.

In this problem, we have a skewed variable and n < 30, hence nothing can be stated about the shape of the sampling distribution for the sample mean.

More can be learned about the Central Limit Theorem at brainly.com/question/16695444

#SPJ1

8 0
2 years ago
Solve the following system of equation.express your answer as an ordered pair in the format with no space between the number or
vladimir1956 [14]
The answer is x=7 and y=-3
8 0
3 years ago
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