The first thing we must do for this case is to define variables.
We have then:
x: weight of the big box
y: weight of the small box.
We now write the system of equations that models the problem:

We apply the graphic solution.
For this, the solution will be the cut point of both lines.
We have then that the solution occurs for the point:
Note: see attached image
Answer:
Weight of each large box: 15.5 Kilograms
Weight of each small box: 13.25 Kilograms
The surface area of a cylinder is:
A=2pr^2+2prh and since r=d/2
A=2p(d^2/4+dh/2)
A=(p/2)(d^2+2dh) and we need 200 of these cylinders...
A=(100p)(d^2+2dh), and using d and h, 3.5cm and 70cm we get:
A=(100p)(3.5^2+2*3.5*7)
A=(100p)(12.25+49)
A=6125p cm^2
A≈19242 cm^2 (to nearest cm^2)
Answer:
-5x + y = -1 or y = 5x - 1
Step-by-step explanation:
5x - y = 9
-5x - 5x
__________
-y = -5x + 9
__ ______
-1 -1
y = 5x - 9
__________________________________________________________
-6 = 5[-1] + b
-5
-1 = b
y = 5x - 1
If you want it in <em>Standard </em><em>Form</em>:
y = 5x - 1
-5x -5x
_________
-5x + y = -1 >> Line in <em>Standard</em><em> </em><em>Form</em>
I am joyous to assist you anytime.
Answer:
Step-by-step explanation:
sin(195º)= -√6+√2/4
cos(195º)=-√6-√2/4
tan(195º)=2-√3