Help me with this please

Mathematics

1 answer:

SVEN [57.7K]3 years ago

4 0

Answer:

An angle of a regular octagon is 135°

(n-2)180°/n

where n is number of sides

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Determine which windsurfer is traveling faster. EXPLAIN YOUR REASONING 5meters per second or 720 feet per minute.

alexdok [17]

The first windsurfer is travelling faster. Solution:
1 meter = 3.28084 feet
The first surfer travels at 5 meters/second so you have to multiply 3.28084 by 5 which equals 16.4042 ft/second
There are 60 seconds in a minute so you will have to multiple 16.4042 ft/second by 60 seconds which equals 984.252 ft/minute

984.252 ft/minute > 720 ft/minute

5 0

3 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

6 0

4 years ago

Write the next three terms of the following sequence 4,5,7,10,14

Law Incorporation [45]

4,5,7,10,14=19,25, 32

8 0

3 years ago

Please answer this question

Free_Kalibri [48]

Answer:

Step-by-step explanation:

$log(3x^{3}) - log(x^{2}) = log(\frac{3x^{3}}{x^{2}})\\log(27) - log(x) = log(\frac{27}{x} )\\$