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goldenfox [79]
2 years ago
10

Simplify 4 times square root 24 minus 4 square root 8 plus square root of 98.

Mathematics
1 answer:
vodomira [7]2 years ago
6 0
The answer is 27.49541288 please give me the brainliest answer I need point s for ansking enlgish questions
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Choose the equivalent system of linear equations that will produce the same solution as the one given below:
skelet666 [1.2K]
D is the answer as the both have solution x=-2 y=3
14x=-28       12(-2)-3y=-33
x=-2              -3y=-9
                       y=3
from the given equation
4x-y=11 eq 1
2x+3y=5 eq 2
x=y-11/4 from equation 1
subsitute this value of x in equation 2
2(y-11/4)+3y=5
y-11+6y=10
7y-11=10
y=3
subsitude this value of y in equation (x=y-11/4)
so x= -2 
thus same solution so ANSWER IS D
3 0
3 years ago
Please help I don’t understand this.
tresset_1 [31]

The average rate of change of <em>g(x)</em> over the interval [2, 8] is given by

(<em>g</em> (8) - <em>g</em> (2)) / (8 - 2)

In other words, it's the slope of the line through the points (2, <em>g</em> (2)) and (8, <em>g</em> (8)).

Use the definition of the function to evaluate it at the points in the numerator:

• 8 ≥ 4, so using the second piece, <em>g</em> (8) = -0.5(8) + 8 = 4

• 2 < 4, so <em>g</em> (2) = 5(2) + 1 = 11

Then the average rate of change is

(<em>g</em> (8) - <em>g</em> (2)) / (8 - 2) = (4 - 11) / 6 = -7/6

3 0
2 years ago
If n = 5 and r = 3 Find "Cr.​
Marat540 [252]

Answer:

Cr = 10

Step-by-step explanation:

To calculate combinations we use the nCr formula: nCr = n! / r! * (n - r)!, where n = number of items, and r = number of items being chosen at a time.

C(n,r)=[?]

C(n,r)=C(5,3)

=\frac{5}{(3!(5-3)!)}

=\frac{5!}{3!*2!}

=10

[RevyBreeze]

3 0
2 years ago
Read 2 more answers
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
kherson [118]

Answer:

The answer is

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

Step-by-step explanation:

Remember that Taylor says that

f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }

For this case

f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

5 0
3 years ago
suppose Q is the midpoint of PR. use the information to find the missing value. PQ equals 3x + 14 and QR equals 7X - 10; find X.
NARA [144]

Answer:

x=6

Step-by-step explanation:

A midpoint is the middle point of a line segment, therefore it is equal distances from both ends of the segment.

This means that PQ and QR have the same length. So all we have to do is set each value equal to each other, and then solve for X.

3x+14=7x-10\\3x+24=7x\\24-4x\\x=6

4 0
3 years ago
Read 2 more answers
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