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3 years ago

10 Troy is building a rectangular garden that is

Mathematics

1 answer:

In-s [12.5K]3 years ago

8 0

Answer:

to ensure 90° corners, the lengths of the diagonal should be the same

Step-by-step explanation:

The Pythagorean theorem can be used to find the expected length of the diagonal. It tells you the square of the diagonal is the sum of the squares of the sides:

d² = (10 ft)² + (6 ft)² = 136 ft²

d = √136 ft ≈ 11.6619 ft ≈ 11 ft 7 15/16 in

The length of each diagonal should be very nearly 11 feet 7 15/16 inches.

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Simplify 4(b-6)+19 ?

Digiron [165]

Answer:

4b -5

Step-by-step explanation:

Perform the indicated multiplication first: 4b - 24 + 19. Next, combine like terms, obtaining 4b -5 (answer)

4 0

3 years ago

Patty's Pies made 2 peach pies using 10 cups of peaches. They made 3 pies using 15 cups of peaches and 4 pies using 20 cups of p

Ivan

It would be 45 cups because each number is multiplied by 5
2 x 5 = 10
3 x 5 = 15
4 x 5 = 20
9 x 5 = 45

7 0

3 years ago

HURRY MATH QUIZ <br> From the list, which terms are like 5x?

ivolga24 [154]

Option 3, is correct.

Just find the one that have the x's only, not the one that is squared or without one. It doesn't matter if the term is a negative or positive.

If you have any further questions, please reach out to me :)

6 0

3 years ago

Read 2 more answers

write and solve a real- world problem involving the multiplication of a fraction and a whole number whose product is between 10

Tomtit [17]

Answer:

Real word Problem:- Jean is working in a pizza shop. She has 60 kg of flour. She has used one-fifth of it for making pizzas. How much flour she used for making pizzas?

Solution:- Quantity of flour she has= 60 kg

The quantity she used in making pizzas= $\frac{1}{5}\ of\ 60$

$=\frac{1}{5}\times60=12\ kg$

hence, she used 12 kg of flour for making pizzas.

Here the multiplication of a fraction and a whole number $=\frac{1}{5}\times60$ and its answer is between 10 and 15, since 10<12<15.

4 0

3 years ago

Read 2 more answers

Which of the following is equivalent to tan2θcos(2θ) for all values of θ for which tan2θcos(2θ) is defined?

Aloiza [94]

Answer:

2sin²θ - tan²θ

Step-by-step explanation:

Given

tan²θcos(2θ)

Required

Simplify

We start by simplifying cos(2θ)

cos(2θ) = cos(θ+θ)

From Cosine formula

cos(A+A) = cosAcosA - sinAsinA

cos(A+A) = cos²A - sin²A

By comparison

cos(2θ) = cos(θ+θ)

cos(2θ) = cos²θ - sin²θ ----- equation 1

Recall that cos²θ + sin²θ = 1

Make sin²θ the subject of formula

sin²θ = 1 - cos²θ

Substitute sin²θ = 1 - cos²θ in equation 1

cos(2θ) = cos²θ - (1 - cos²θ)

cos(2θ) = cos²θ - 1 +cos²θ

cos(2θ) = cos²θ + cos²θ - 1

cos(2θ) = 2cos²θ - 1

Substitute 2cos²θ - 1 for cos(2θ) in the given question

tan²θcos(2θ) becomes

tan²θ(2cos²θ - 1)

Open brackets

2cos²θtan²θ - tan²θ

------------------------

Simplify tan²θ

tan²θ = (tanθ)²

Recall that tanθ = sinθ/cosθ

So, we have

tan²θ = (sinθ/cosθ)²

tan²θ = sin²θ/cos²θ

------------------------

Substitute sin²θ/cos²θ for tan²θ

2cos²θtan²θ - tan²θ becomes

2cos²θ(sin²θ/cos²θ) - tan²θ

Open bracket (cos²θ will cancel out cos²θ) to give

2(sin²θ) - tan²θ

2sin²θ - tan²θ

Hence, the simplification of tan²θcos(2θ) is 2sin²θ - tan²θ

Option E is correct

7 0

3 years ago