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CaHeK987 [17]
3 years ago
14

How do i solve x^2-11x+14=0 using the quadratic formula

Mathematics
2 answers:
8_murik_8 [283]3 years ago
8 0
<u />x^2-11x+14=0 \\ \\&#10;a=1 \\ b=-11 \\ c=14 \\ b^2-4ac=(-11)^2-4 \times 1 \times 14=121-56=65 \\&#10;x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-(-11) \pm \sqrt{65}}{2 \times 1}=\frac{11 \pm \sqrt{65}}{2} \\&#10;\boxed{x=\frac{11 - \sqrt{65}}{2} \hbox{ or } x=\frac{11+\sqrt{65}}{2}}
rosijanka [135]3 years ago
7 0
X² - 11x + 14 = 0
x = <u>-(-11) +/- √((-11)² - 4(1)(14))
</u>                        2(1)
x = <u>11 +/- √(121 - 56)</u>
                   2
x = <u>11 +/- √(65)</u>
               2
x = <u>11 +/- 8.062257748</u>
                     2
x = <u>11 + 8.062257748</u>      x = <u>11 - 8.062257748</u>
                    2                                       2
x = <u>19.062257748</u>            x = <u>2.937742252</u>
                 2                                      2
x = 1.906225775              x = 1.468871126
<u />
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