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zavuch27 [327]
2 years ago
14

Colin is skateboarding and is riding a rail. The rail is attached to two poles. The first pole is 80 cm tall and the

Mathematics
1 answer:
Vinvika [58]2 years ago
5 0

Answer:

\sqrt{4.49m}

Step-by-step explanation:

the unit of length is meter,

so, 80cm=0.8cm, 10cm=0.1m

the length of the rail=\sqrt{(0.8-0.1)^2+2^2}

                                  =\sqrt{4.49m}

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Pls help me<br> also pls put the right answer
Y_Kistochka [10]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
(PLESE HELP) Factor the following expression. Simplify your answer.
mars1129 [50]

The factor of the expression 5p(p + 2)^{\frac{2}{3} }  + 4(p + 2)^{\frac{1}{3} } is(p + 2)^{\frac{2}{3} } (5p^{3}  + 10p^{2}  + 20p + 4)

To answer the question, we need to know what factorization is

<h3>What is factorization?</h3>

Factorization is the process of breaking down an expressing into a simpler form containing its factors.

Since

5p(p + 2)^{\frac{2}{3} }  + 4(p + 2)^{\frac{1}{3} }

Since (p + 2)^{\frac{1}{3} } is common, we factor it out. So, we have

(p + 2)^{\frac{2}{3} } (5p(p + 2)^{2}  + 4)

Expanding the bracket, we have

(p + 2)^{\frac{2}{3} } (5p(p^{2}  + 2p + 4) + 4) = (p + 2)^{\frac{2}{3} } (5p^{3}  + 10p^{2}  + 20p + 4)

So, the factor of the expression 5p(p + 2)^{\frac{2}{3} }  + 4(p + 2)^{\frac{1}{3} } is(p + 2)^{\frac{2}{3} } (5p^{3}  + 10p^{2}  + 20p + 4)

Learn more about factorization here:

brainly.com/question/11579257

#SPJ1

8 0
2 years ago
Mark is planning to swim the 200-yard freestyle event at the next
bazaltina [42]
Mark will swim 182.88 meters
7 0
1 year ago
Percy said that any real number for k would cause the system of equations to have no solution. Explain the error in Percy’s stat
MatroZZZ [7]

Answer:

Except k=7, any real number for k would cause the system of equations to have no solution.

Step-by-step explanation:

In general a system of equations can be represented as ax+by=c and dx+ey=f. In order this system of equations to have NO SOLUTIONS a/d=b/a≠c/f. In our example a=6, b=4, c=14, d=3, e=2 and f=k. To apply the formula above, 6/3=4/2≠14/k. Hence k≠7. It can be concluded that except k=7, any real number for k would cause the system of equations to have no solutions.

Just for information, if k=7 the system will have infinitely many solutions.

5 0
3 years ago
Read 2 more answers
Look at the figure shown below:
kow [346]

Answer:  b) two sides and the included angle are congruent

<u>Step-by-step explanation:</u>

  RS = QS                 SIDES are congruent

∠PSR ≡ ∠PSQ         ANGLES are congruent

 PS = PS                  SIDES are congruent

ΔPSR ≡ ΔPSQ by the Side-Angle-Side (SAS) Congruency Theorem

Since we know the triangles are congruent, we can state that their parts are congruent:

Congruent-Parts of-Congruent-Triangles are-Congruent (CPCTC)

8 0
3 years ago
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