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zavuch27 [327]
2 years ago
14

Colin is skateboarding and is riding a rail. The rail is attached to two poles. The first pole is 80 cm tall and the

Mathematics
1 answer:
Vinvika [58]2 years ago
5 0

Answer:

\sqrt{4.49m}

Step-by-step explanation:

the unit of length is meter,

so, 80cm=0.8cm, 10cm=0.1m

the length of the rail=\sqrt{(0.8-0.1)^2+2^2}

                                  =\sqrt{4.49m}

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Given that when x is reduced by 17% the answer is y, express x in terms of y.
Dima020 [189]
X - 0.17 = y
 
add 0.17 to both sides

x = y + 0.17
3 0
3 years ago
Evaluate 2^2⋅4^3=<br><br>Your answer<br><br><br>​
ivanzaharov [21]

Answer:

256

Step-by-step explanation:

First, handle the exponent:

2²=4 (2*2=4)     and     4³=64 (4*4=16*4=64)

Now multiply those two outcomes:

4*64=<u>256</u>

This equation is also known as 4⁴

6 0
3 years ago
Estimates of the number of cells in the human body vary over an order of magnitude.​ Indeed, the precise number varies from one
Amiraneli [1.4K]

Answer:

a) 2.00 × 10¹⁰;  b) 2.00 × 10¹³

Step-by-step explanation:

a) No. of cells in 1 cm³

\text{No. of cells} =\text{1 cm}^{3} \times\left( \dfrac{\text{1 m}}{\text{100 cm}}\right )^{3} \times \left (\dfrac{1 \, \mu \text{m} }{10^{-6}\,\text{ m}}\right )^{3} \times  \dfrac{\text{1 cell}}{\text{50 $\,\mu$m}^{3}} = \mathbf{2.00 \times 10^{10}} \textbf{ cells}

b) No. of cells in 1 L

\text{No. of cells} =  \text{1 L} \times \dfrac{\text{1000 cm}^{3}}{\text{1 L}} \times \dfrac{2 \times 10^{10} \text{ cells}}{\text{1 cm}^{3}} = \mathbf{2.00 \times 10^{13}} \textbf{ cells}

7 0
3 years ago
Solve the problem.
MA_775_DIABLO [31]
Circumference = 2πr

r = 9

Circumference = 2π(9)
Circumference = 18π
Circumference = 18(3.14)
Circumference = 56.52

Distance: 56.52 meters
8 0
3 years ago
If w = 9, x = 10, and y = 3, what does 6x over 5y equal?
nirvana33 [79]

Answer:

6x = 6 (10) => 60

5y = 5 (3) => 15

\frac{6x}{5y}  =  >  \frac{60}{15}  =  > 4

hope that helps uhh!!

3 0
3 years ago
Read 2 more answers
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